In the adjoining figure, $PQ\parallel CA$ and lengths are given in centimetres. The length of $BC$ is

In the adjoining figure, $MN\parallel QR$ . If $PN=3.6 cm, NR=2.4 cm$ and $PQ=5 cm$, then $PM$ is

$D$ d and $E$ E are respectively the points on the sides $AB$ and $AC$ of a $△ABC$ such that $AD=2 cm, BD=3 cm, BC=7.5 cm$ and $DE\parallel BC$. Then the length of $DE$ is

In the adjoining figure, $△ABC~△QPR.$ Then $\angle R$ is 

In the adjoining figure, $△ABC~△QPR.$ Then the value of $x$ is

If in two triangles $ABC$ and $PQR, \frac{AB}{QR}=\frac{BC}{PR}=\frac{CA}{PQ},$ then

In triangles $ABC$ and $DEF$, $\angle B=\angle E, \angle F=\angle C$ and $AB=3DE$, then two triangles are

In the adjoining figure, if $D, E$ and $F$ are mid-points of the sides $BC,CA$ and $AB$ respectively, then the two triangles $ABC$ and $DEF$ are

In the adjoining figure , $AB\parallel DE$. The length of $CD$ is