In the circuit shown (figure), the switch $S_2$ is closed first and is kept closed for a long time. Now, $S_1$ is closed, Just after that instant, the current thought $S_1$ is,

Each resistor in the following circuit (figure) has a resistance of $2 \mathrm{M}\mathrm{\Omega }$ and the capacitors have a capacitance of $1 \mathrm{\mu }\mathrm{F}$. The battery voltage is $3 \mathrm{V}$. The voltage across the resistor $A$ in the following circuit in steady state is,

Initially, switch $S$ is connected to position $1$ for a long time (figure). The net amount of heat generated in the circuit after it is shifted to position $2$ is

The switch $S$ in the circuit diagram (figure) is closed at $t=0$. The charge on capacitors at any time $t$ is,

The charge on the capacitor in steady-state in the circuit shown (figure) is

In the circuit shown (Figure), if switches $S_1$, and $S_2$ have been closed for a long time, then the charge on the capacitor

The circuit shown in figure consists of a battery of emf, $\epsilon =10 \mathrm{V}$, a capacitor of capacitance $C=1.0 \mathrm{\mu }\mathrm{F}$ and three resistors of values, $R_1=2 \mathrm{\Omega }$, $R_2=2 \mathrm{\Omega }$ and $R_3=1 \mathrm{\Omega }$. Initially, the capacitor is completely uncharged and the switch $\mathrm{S}$ is open. The switch $\mathrm{S}$ is closed at $t=0$. Then,