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In the circuit shown in adjoining figure, $E = 10 V, R_{1} = 1 Ω, R_{2} = 2 Ω, R_{3} = 3 Ω$ and $L = 2 H$ . Calculate the value of current $i_{1}, i_{2}$ and $i_{3}$ immediately after key $S$ is closed.

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Important Questions on Electromagnetic Induction

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Beta Question Bank for Medical: Physics>Chapter 27 - Electromagnetic Induction>BEGINNER'S BOX - 6>Q 2

The mutual inductance between a primary and secondary circuits is

0.5 H

. The resistance of the primary and the secondary circuits are

20 Ω

and

5 Ω

respectively. To generate a current of

0.4 A

in the secondary, current in the primary must be changed at the rate of

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Beta Question Bank for Medical: Physics>Chapter 27 - Electromagnetic Induction>BEGINNER'S BOX - 6>Q 3

Two coils

A and B

having turns

300 and 600

, respectively, are placed near each other on passing a current of

3.0 A in A

, the flux linked with

A is 1.2 \times 10^{- 4} W

and with

B it is 9.0 \times 10^{- 5} W

. The mutual inductance of the system is,

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Beta Question Bank for Medical: Physics>Chapter 27 - Electromagnetic Induction>BEGINNER'S BOX - 6>Q 4

If the current in a primary circuit is,

I = I_{0} \sin ω t

and the mutual inductance is

M

, then the value of induced voltage in secondary circuit will be,

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Beta Question Bank for Medical: Physics>Chapter 27 - Electromagnetic Induction>BEGINNER'S BOX - 6>Q 5

An a.c. of 50 Hz and 1 A peak value flows in primary coil transformer whose mutual inductance is 1.5 H. Then peak value of induced emf in secondary is :-

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Beta Question Bank for Medical: Physics>Chapter 27 - Electromagnetic Induction>BEGINNER'S BOX - 6>Q 6

The number of turn of primary and secondary coil of a transformer is 5 and 10 respectively and the mutual inductance is 25 H. If the number of turns of the primary and secondary is made 10 and 5, then the mutual inductance of the coils will be :-

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Beta Question Bank for Medical: Physics>Chapter 27 - Electromagnetic Induction>BEGINNER'S BOX - 6>Q 7

The length of a solenoid is 0.3 m and the number of turns is 2000. The area of cross-section of the solenoid is 1.2 x 10^–3m². Another coil of 300 turns is wrapped over the solonoid. A current of 2A is passed through the solenoid and its direction is changed in 0.25 sec. then the induced emf in coil :-

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Beta Question Bank for Medical: Physics>Chapter 27 - Electromagnetic Induction>BEGINNER'S BOX - 6>Q 8

Two conducting loops of radi