Modern Approach to Chemical Calculations>Chapter 8 - Electrolysis and Electrolytic Conductance>Objective Problems>Q 11

HARD

JEE Main

IMPORTANT

Earn 100

In the electrolysis of ${CuCl}_{2}$ solution ( $aqueous$ ) with $Cu$ electrodes, the weight of cathode increased by $3.2$ $g$ . In the anode,

60% studentsanswered this correctly

Important Questions on Electrolysis and Electrolytic Conductance

HARD

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 8 - Electrolysis and Electrolytic Conductance>Objective Problems>Q 12

The current required to displace

0.1 g

of

H_{2}

in

10

seconds will be

EASY

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 8 - Electrolysis and Electrolytic Conductance>Objective Problems>Q 13

The charge of an electron is

1.6 \times 10^{- 19} coulomb

. How many electrons per second pass through a cross section of a

Cu

wire carrying

10^{- 16}

ampere

?

HARD

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 8 - Electrolysis and Electrolytic Conductance>Objective Problems>Q 14

96500 coulombs

deposit

107.9 g

of

Ag

from its solution. If

e = 1.6 \times 10^{- 19} coulomb

, calculate the number of electrons per mole.

HARD

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 8 - Electrolysis and Electrolytic Conductance>Objective Problems>Q 15

A current of

2 ampere

passing for

5

hours through a molten tin salt deposits

22.2 g

of tin. The oxidation state of the tin in the salt is

MEDIUM

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 8 - Electrolysis and Electrolytic Conductance>Objective Problems>Q 16

The cost at $5 paise / kWh$ of operating an electric motor for $8 hours$ which takes $15 ampere$ at $110 V$ is:

Hint: Electric Power, $P = V I$

HARD

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 8 - Electrolysis and Electrolytic Conductance>Objective Problems>Q 17

One Faraday of current was passed through the electrolytic cells placed in a series containing the solutions of

{Ag}^{+}, {Ni}^{+ +}

and

{Cr}^{+ + +}

, respectively. The amounts of

Ag

(atomic weight

= 108

),

Ni

(atomic weight

= 59

) and

Cr

(atomic weight

= 52

) deposited will be

HARD

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 8 - Electrolysis and Electrolytic Conductance>Objective Problems>Q 18

The time required to remove electrolytically one-fourth of

Ag

from

0.2 L

of

0.1 M {AgNO}_{3}

solution by a current of

0.1 amp

is

HARD

JEE Main

IMPORTANT

Modern Approach to Chemical Calculations>Chapter 8 - Electrolysis and Electrolytic Conductance>Objective Problems>Q 19

In the electrolysis of $H_{2} {SO}_{4}$ , $9.72 L$ and $2.35 L$ of $H_{2}$ and $O_{2}$ , respectively, were liberated. The number of equivalent of persulphuric acid $(H_{2} S_{2} O_{8})$ produced is

(Hint: The reactions are $2 H_{2} {SO}_{4} \to H_{2} S_{2} O_{2} + H_{2}$ and $2 H_{2} O \to 2 H_{2} + O_{2}$ )