In the figure, the voltmeter is not ideal. If the voltmeter is removed from $R_1$, and then put across $R_2$, what will be the effect on current $I$? Given $R_1>R_2$

Three ammeters $A, B$ and $C$ of resistances $R_A, R_B$ and $R_C,$ respectively, are joined as shown in the figure.

When some potential difference is applied across the terminals $T_1$ and $T_2,$ their readings are $I_A, I_B$ and $I_C,$ respectively, then

A battery of emf ${\mathrm{\epsilon }}_0=5 \mathrm{V}$ and internal resistance $5 \mathrm{\Omega }$ is connected across a long uniform wire $AB$ of length $1 \mathrm{m}$ and resistance per unit length $5 \mathrm{\Omega } {\mathrm{m}}^{-1}$. Two cells of ${\mathrm{\epsilon }}_1=1 \mathrm{V}$ and ${\mathrm{\epsilon }}_2=2 \mathrm{V}$are connected as shown in the figure.

A circuit is shown below:

A circuit contains an ideal battery, three resistors and two ideal ammeters. The ammeters read $0.2 \mathrm{A}$ and $0.3 \mathrm{A}$. After two of the resistors are switched, the readings of the ammeters did not change. Find the battery current.

In the circuit shown, battery, ammeter and voltmeter are ideal and the switch $S$ is initially closed as shown. When switch $S$ is opened,