In the figure shown, if the diode forward voltage drop is 0.2 V, the voltage difference between $A$ and $B$ is

Explain the working of Daniel cell with a neat diagram.

A battery of e.m.f $12 \mathrm{V}$ and internal resistance $0.5 \mathrm{\Omega }$ is charged by a battery charger which supplies a $132 \mathrm{V}$ d.c. supply using a series resistance of $11.5 \mathrm{\Omega }$. What is the terminal voltage of the battery during charging?

The variation of terminal potential difference $\left(V\right)$ with current flowing through as cell is as shown

The $\mathrm{emf}$ and internal resistance of the cell are

In the arrangement shown in figure, the current through $5\mathrm{\Omega }$ resistor is


  

In the circuit shown, the current in $3 \mathrm{\Omega }$ resistor is

The reading on a high resistance voltmeter, when a cell is connected across it, is $2.0V$. When the terminals of the cell are also connected to a resistance of  $3 \Omega$  as shown in the circuit, the voltmeter reading drops to $1.5V$. The internal resistance of the cell is :

Two insulating plates are both uniformly charged in such a way that the potential difference between them is $V_2-V_1=20 \mathrm{V}$. (i.e., the plate $2$ is at a higher potential). The plates are separated by $d=0.1 \mathrm{m}$ and can be treated as infinitely large. An electron is released from rest on the inner surface of the plate $1$. What is its speed when it hits plate $2$? $(\mathrm{e}=1.6\times {10}^{-19} \mathrm{C}, {\mathrm{m}}_0=9.11\times {10}^{-31} \mathrm{kg})$