In the figure shown below, the charge on the left plate of the $10 \mathrm{\mu F}$ capacitor is $-30 \mathrm{\mu C}.$ The charge on the right plate of the $6 \mathrm{\mu F}$ capacitor is:

In the figure shown, after the switch $S$ is turned position $A$ to position $B,$ the energy dissipated in the circuit in terms of capacitance $C$ and total charge $Q$ is: 

The$V$ vs $x$ plot for six identical metal plates of cross-sectional area $A$ is as shown. The equivalent capacitance between $2$ and $5$ is (adjacent plates are placed at a separation $d$),

A parallel plate capacitor of capacitance $C$ is as shown. A thin metal plate $A$ is placed between the plates of the given capacitor in such a way that its edges touch the two plates as shown. The capacity now becomes,