In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer If
(1) X > Y
(2) X ≥ Y
(3) X < Y
(4) X ≤ Y
(5) X = Y or the relationship cannot be established

 I.  ${ x }^{ 5 }\times 5={ x }^{ 3 }\times 80$
 II.  ${ y }^{ 2/5 }\times 9=36\div { y }^{ 3/5 } $

Is the following situation possible? If so, determine their present ages. The sum of the ages of two friends is $20 \mathrm{years}$. Four years ago, the product of their ages in years was $48.$

A motor boat whose speed is $18 \mathrm{km}/\mathrm{hour}$ in still water takes $1 \mathrm{hour}$ more to go $24 \mathrm{km}$ upstream than to return downstream to the same spot. If the speed of the stream is $x \mathrm{km}/\mathrm{hour}$, find $x$.

Find two consecutive odd positive integers, sum of whose square is $290$.

The sum of the areas of two squares is $400 sq.m.$ If the difference between their perimeters is $16m$, find the sides of two squares

The sum of a number and its reciprocal is $\frac{26}{5}$. Find the number.