An aqueous solution containing 288 g of a non-volatile compound, having the stoichiometric composition C n H 2 n O n in 90 . 0 g of water, boils at 101 . 24 ° C under 1 . 00 atm pressure. What is the molecular formula of the given compound?

The formula used for calculating elevation in boiling point is, ∆ T b = K b × m . Where, K b = molal elevation constant and m = molality. Molality can be written as m = w × 1000 GMM × W where w = weight of the solute, W = weight of the solvent and GMM = Gram molecular mass. GMM of the solute ( C n H 2 n O n ) = 12 n + 2 n + 16 n = 30 n . Hence, putting the values in the above equations, we get, 1 . 24 = 0 . 512 × 288 × 1000 30 n × 90 n = 1321 . 29 30 n = 44 Therefore, n = 44 and GMM = 30 × 44 = 1320 .

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In the following statements, which is/are false for a solution of chloroform and acetone?

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Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part - 2 JEE Main & Advanced>Chapter 2 - Solutions>DPP 2.2>Q 18

Composition of an azeotrope

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Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part - 2 JEE Main & Advanced>Chapter 2 - Solutions>DPP 2.2>Q 19

The diagram given below depicts the boiling point as the function of composition of the mixture of ${CCl}_{4}$ and ${SiCl}_{4}$ . Which of the following statement about the diagram is/are true?

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Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part - 2 JEE Main & Advanced>Chapter 2 - Solutions>DPP 2.3>Q 1

Explain why on the addition of

1

mole of

NaCl

1 L

of water, the boiling point of water increases, while the addition of a mole of methyl alcohol to

1 L

of water, decreases its boiling point?

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Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part - 2 JEE Main & Advanced>Chapter 2 - Solutions>DPP 2.3>Q 2

What is the reason that the vapour pressure of an aqueous solution of glucose is lower than that of water?

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Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part - 2 JEE Main & Advanced>Chapter 2 - Solutions>DPP 2.3>Q 3

2 g

each of two non-electrolyte solutes

A

and

B

(molar mass of

A

is greater that of

B

) are dissolved separately in

50 g

each of the same solvent. Which one will show a greater elevation in the boiling point?

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Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part - 2 JEE Main & Advanced>Chapter 2 - Solutions>DPP 2.3>Q 3

An aqueous solution containing

288 g

of a non-volatile compound, having the stoichiometric composition

C_{n} H_{2 n} O_{n}

90.0 g

of water, boils at

101.24 ° C

under

1.00

atm pressure. What is the molecular formula of the given compound?

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Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part - 2 JEE Main & Advanced>Chapter 2 - Solutions>DPP 2.3>Q 4

A solution contains

30 g

of a non-volatile solute in exactly

90 g

of water, it has a vapour pressure

21.85 mm

Hg

25 ° C .

Further,

18 g

of water is then added to the solution, the new vapour pressure becomes

22.15 mm

Hg

25 ° C

. Calculate the molar mass of the solute.

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Chapterwise/Topicwise Daily Practice Problems (DPP) Physical Chemistry Part - 2 JEE Main & Advanced>Chapter 2 - Solutions>DPP 2.3>Q 4

A solution contains $30 g$ of a non-volatile solute in exactly $90 g$ of water, its vapour pressure is $21.85 mm$ of $Hg$ at $25 ° C .$ Further, $18 g$ of water is then added to the solution, the new vapour pressure becomes $22.15 mm$ of $Hg$ at $25 ° C$ . Calculate the vapour pressure of water at $25 ° C$ .

In the following statements, which is/are false for a solution of chloroform and acetone?

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