In the given arrangement, the loop is moved with constant velocity $v$ in a uniform magnetic field $B$ in a restricted region of width $a\mathit{.}\mathit{ }$The time for which the emf is induced in the circuit is:

 

A thin semicircular conducting ring of radius $R$ is falling with its plane vertical in a horizontal magnetic induction $\overrightarrow{\mathit{B}}$ . At the position $\mathrm{MNQ}$ the speed of the ring is $v\mathit{ }$then the potential difference developed across the ring is:

Figure shows a square loop of side $1 \mathrm{m}$ and resistance $1 \mathrm{\Omega }$. The magnetic field on left side of line $\mathrm{PQ}$ has a magnitude $B=1.0 \mathrm{T}$. The work done in pulling the loop out of the field uniformly in $1 \mathrm{s}$ is

Figure shows a conducting loop being pulled out of a magnetic field with a constant speed $\mathrm{v}$. Which of the four plots shown in figure may represent the power delivered by the pulling agent as a function of the constant speed $\mathrm{v}$.

A long conductor $\mathrm{AB}$ lies along the axis of a circular loop of radius $R$.If the current in the conductor $\mathrm{AB}$ varies at the rate of $I$ ampere/second, then the induced emf in the loop is

A rod of length $10 \mathrm{cm}$ made up of conducting and non-conducting material (shaded part is non-conducting). The rod is rotated with constant angular velocity $10 \mathrm{rad} {\sec }^{-1}$about point $\mathrm{O}$, in constant and uniform magnetic field of $2$Tesla as shown in the figure. The induced emf between the point $\mathrm{A}$ $\mathrm{B}$and B of rod will be

Figure shows a conducting disc rotating about its axis in a perpendicular uniform and constnat magnetic field $\mathrm{B}$. A resistor of resistance $R$ is connected between the centre and the rim. The radius of the disc is $5.0 \mathrm{cm}$, angular speed $\omega =40 \mathrm{rad} {\mathrm{s}}^{-1}, B=0.10 \mathrm{T}$ $R = 1 \mathrm{\Omega }$. The current through the resistor is