In the given circuit, a charge of $+80 \mathrm{\mu C}$ is given to the upper plate of the $4 \mu \mathrm{F}$ capacitor. Then in the steady-state, the charge on the upper plate of the $3 \mathrm{\mu F}$ capacitor is

Assertion: If the potential difference across a plane parallel plate capacitor is doubled then the potential energy of the capacitor becomes four times under all conditions.

Reason: The potential energy $U$ stored in the capacitor is $U=\frac{1}{2}V{C}^2,$ where $C$ and $V$ have usual meanings.

Assertion : A charged plane parallel plate capacitor has half interplanar region (l) filled with dielectric slab. The other half region II has air, Then the magnitude of net electric field in region $I$ is less than that in region Il.

Reason : In a dielectric medium induced (or polarised) charges tend to increase the electric field inside the dielectric.

Assertion : A parallel plate capacitor is charged to a potential difference of $100 \mathrm{V},$ and disconnected from the voltage source. A slab of dielectric is then slowly inserted between the plates. Compared to the energy before the slab was inserted, the energy stored in the capacitor with the dielectric is decreased.

Reason : When we insert a dielectric between the plates of a capacitor, the induced charges tend to draw the dielectric into the field ( just as neutral objects are attracted by charged objects due to induction). We resist this force while slowly inserting the dielectric, and thus do negative work on the system, removing electrostatic energy from the system.

Assertion : The circuits containing capacitor be handled cautiously even when there is no current.

Reason : A charged capacitor, can discharge through our body and harm us.

Assertion : Increasing the charge on the plates of a capacitor means increasing the capacitance.

Reason : Because $Q=CV\Rightarrow Q\propto C.$

Assertion: The capacitance of a capacitor depends on the shape, size and geometrical placing of the conductors and its medium between them.

Reason: When a charge $q$ passes through a battery of emf $E$ from the negative terminal to an positive terminal, an amount $qE$ of work is done by the battery.

Assertion :- A dielectric slab is inserted between the plates of an isolated charged capacitor. The charge on the capacitor will remain the same.

Reason :- Charge on an isolated system is conserved.

Assertion : If three capacitors of capacitance $C_1<C_2<C_3$ are connected in parallel then their equivalent capacitance $C_p>C_s$

Reason : $\frac{1}{C_p}=\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}$