In the given circuit, all the capacitors are initially uncharged. After closing the switch $S_1$ for a long time suddenly $S_2$ is also closed and kept closed for a long time. Total heat produced after closing $S_2$ will be :

In the circuit shown, find $C$ if the effective capacitance of the whole circuit is to be $0.5 \mu F.$ All values in the circuit are in $\mu F.$

Calculate the amount of charge on capacitor of $4 \mathrm{\mu F}.$ The internal resistance of battery is $1\mathrm{\Omega }:$

The figure shows a capacitor of capacitance $\mathrm{C}$ connected to a battery via a switch, having a total charge ${\mathrm{Q}}_0$ on it, in steady-state. When the switch $\mathrm{S}$ is turned from position $\mathrm{A}$ to position $\mathrm{B}$, the energy dissipated in the circuit is

In the given circuit diagram,

$E=5 \mathrm{V}, r=1 \mathrm{\Omega }, R_2=4 \mathrm{\Omega }, R_1=R_3=1 \mathrm{\Omega }$ and $C=3 \mu \mathrm{F}$

Then, what will be the numerical value of charge on each plates of the capacitor.

Five identical capacitors, of capacitance $20 \mathrm{\mu F}$ each, are connected to a battery of $150 \mathrm{V},$ in a combination as shown in the diagram. What is the total amount of charge stored?

In the circuit shown in the figure, the total charge is $750 \mu C$ and the voltage across capacitor $C_2$ is $20 \mathrm{V}$. Then the charge on capacitor ${\mathrm{C}}_2$ is :

Three capacitances, each of 3 $\mu \text{F}$, are provided. These cannot be combined to provide the resultant capacitance of :

Figure shows a network of capacitors where the number indicates capacitances in micro Farad. The value of capacitance C if the equivalent capacitance between point A and B is to be $1 \mu F$ is :

For the arrangement of capacitors as shown in the circuit, the effective capacitance between point $A$ and $B$ is (capacitance of each capacitor is $4\mu F)$

In the circuit shown, charge on the $5\mu \mathrm{F}$  capacitor is :

The equivalent capacitance between $A$ and $B$ is,