In the given diagram $△\mathrm{ABC}$ is a right-angled triangle, $\angle \mathrm{ABC} = {90}^0$, BD I AC. If AB:AC = 3:5 and area of $△\mathrm{ABD}$ is $90{\mathrm{cm}}^2$, then the area of  $△$ABC (in cm²) is:

 

In the diagram given below RT $\perp$PQ. S is a point on QR such that: $\angle$QPS = 40°, $\angle$TRQ = 30°, then $\angle$PSQ = ?

In the given diagram if AB||CD||EF then which of the given options is true.

In the given figure PR = QR = PS, $\angle$ZPSR = X, $\angle$TPS =90° then x = ?

In the given diagram two concentric circles with centre O are shown. If $\angle$$\mathrm{AOB} = 120°$ Then $\angle$$\mathrm{OAP} =$