In the shown arrangement of the experiment of the metre bridge, if length $\mathrm{AC}$ corresponding to null deflection of galvanometer is $x$, what would be its value if the radius of the wire $\mathrm{AB}$ is doubled? 

$AB$is a wire of uniform resistance. The galvanometer $G$ shows no current when the length $AC=20 \mathrm{cm}$ and $CB=80 \mathrm{cm}.$ The resistance $R$ is equal to

A metre bridge is set up as shown, to determine an unknown resistance $X$ using a standard $10 \mathrm{\Omega }$ resistor. The galvanometer shows null point when the tapping key is at $52 \mathrm{cm}$ mark. The end-corrections are $1 \mathrm{cm}$ and $2 \mathrm{cm}$ respectively for the ends $\mathrm{A}$ and $\mathrm{B}$. The determined value of $X$ is 

In the shown arrangement of a meter bridge, if $AC$ corresponding to null deflection of galvanometer is $x$, what would be its value if the radius of the wire $AB$ is doubled?

In a practical Wheatstone bridge circuit as shown, when one more resistance of $100 \mathrm{\Omega }$ is connected in parallel with an unknown resistance $x$, then, the ratio $\frac{l_1}{l_2}$ becomes $2$. If $l_1$ is the balance length and $AB$ is a uniform wire, then the value of $x$ must be 

The meter-bridge wire $AB$shown in figure is $50 \mathrm{cm}$ long. When $AD=30 \mathrm{cm}$, no deflection occurs in the galvanometer. Find$R$.

In the given circuit, no current is passing through the galvanometer. If the cross-sectional diameter of the wire $AB$ is doubled, then for null point of galvanometer, the value of $AC$ would be

With resistances $P$ and $Q$ in the left and right gaps of a metre bridge, the balance point divides the wire in the ratio $\frac{1}{3}.$ When $P$ and $Q$ are increased by $40 \mathrm{\Omega }$, the balance point divides the wire in the ratio $\frac{3}{5}.$ The values of $P$ and $Q$ will be respectively,