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In the situation shown in the diagram, the system is in equilibrium. All the strings, spring and pulley are light. Just after cutting the string AB,

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Important Questions on Laws of Motion

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Agniveer Vayu
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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 4
Match the following (Take the relative strength of the strongest fundamental forces in nature as one)
 
I II
Fundamental forces in nature Relative strength
(A) Strong nuclear force (e) 10-2
(B) Weak nuclear force (f) 1
(C) Electromagnetic force (h) 10-13
(D) Gravitational force (i) 10-39


The correct match is
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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 5
Let F, FN and f denote the magnitudes of the contact force, normal force and the frictional force exerted by one surface on the other kept in contact. If none of these is zero, then:
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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 6
Two boys of masses 10 kg and 8 kg are moving along a vertical rope, the former climbing up with the acceleration of 2 m s-2 while the later coming down with a uniform velocity of 2 m s-1. Then tension in the rope at the fixed support is  (Take g = 10 m s-2 )
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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 7
A spring of force constant k is cut into two pieces such that one piece is double the length of the other. Then the long piece will have a force constant of
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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 8
In a situation, the contact force by a rough horizontal surface, on a body placed on it, has constant magnitude. If the angle between this force and the vertical is decreased, the frictional force between the surface and the body will
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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 9
A block is on a rough inclined plane. To keep it at rest force required is maximum 2 N downward or maximum 10 N upward. Find the coefficient of friction

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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 10
A variable force F=25t acts on a body of mass 10 kg kept on a rough horizontal surface μs⁡=0.6 μk=0.4. The velocity of the body at t=4 s is,
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Achieve Indian Airforce Agniveer Vayu Physics Practice Book>Chapter 5 - Laws of Motion>Exercise>Q 11

A block of mass 5 kg, resting on a horizontal surface, is connected by a cord, passing over a light frictionless pulley to a hanging block of mass 5 kg. The coefficient of kinetic friction between the block and the surface is 0.5. Tension in the cord is [Take g=9.8 m s-2]

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