In the structure of ${\mathrm{H}}_2{\mathrm{CSF}}_4$, to decide the plane in which $\mathrm{C}=\mathrm{S}$ is present, the following bond angle values are given:
Axial $\mathrm{FSF}$ angle (idealised $=180°$)$\Rightarrow 170°$

Equatorial $\mathrm{FSF}$ angle (idealised $=120°$) $\Rightarrow 97°$

After deciding the plane of double bond, which of the following statement is/are correct?

Consider the following statements;

($\mathrm{I}$) The hybridisation found in cation of solid ${\mathrm{PCl}}_5$ is ${\mathrm{sp}}^3$.

($\mathrm{II}$) In ${\mathrm{AB}}_2{\mathrm{L}}_2$ type, the $\mathrm{BAB}$ bond angle is always greater than the normal tetrahedral bond angle.

($\mathrm{III}$) In ${\mathrm{ClO}}_3^{-}, {\mathrm{NH}}_3$ and ${\mathrm{XeO}}_3$, the hybridisation and the number of lone pairs on the central atoms are the same.

($\mathrm{IV}$) In ${\mathrm{P}}_4$ molecule, there are six $\mathrm{P}-\mathrm{P}$ bonds and four lone pairs of electrons.

Of these statements :

The following molecules/species have been arranged in the order of their increasing bond orders. Identify the correct order.

($\mathrm{I}$) ${\mathrm{O}}_2$;

($\mathrm{II}$) ${\mathrm{O}}_2^{-}$;

($\mathrm{III}$) ${\mathrm{O}}_2^{2-}$;

($\mathrm{IV}$) ${\mathrm{O}}_2^{+}$;