Initially, car $A$ is $10.5 \mathrm{m}$ ahead of car $B$. Both start moving at time $t=0$ in the same direction along a straight line. The velocity-time graph of the two cars is shown in the figure. The time when the car $B$ will catch the car $A$ will be

 

The acceleration-time graph of a particle moving along a straight line is as shown in the figure. In what time will the particle acquire its initial velocity?

Which of the following situations is represented by the velocity-time graph shown in the diagram?

The velocity-time graph of a body moving in a straight line is shown. The displacement of the body in $10 \mathrm{s}$ is 

The variation of velocity of a particle moving along a straight line is shown in the figure. The distance travelled by the particle in $12 \mathrm{s}$ is

Acceleration $\left(a\right)$-displacement $\left(s\right)$ graph of a particle moving in a straight line is as shown in the figure. The initial velocity of the particle is zero. The velocity $\left(v\right)$-displacement $\left(s\right)$ graph of the particle would be

In the following velocity-time graph of a body, the distance travelled by the body and its displacement during $5 \mathrm{s}$ (in metres) will respectively be

The figure shows velocity $\left(v\right)$ versus time $\left(t\right)$ graphs for two cyclists, $A$ and $B$, moving along the same straight segment of a highway from the same point. The second cyclist starts moving at $t=3 \min$. At what time, do the two cyclists meet?