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John has x children by his first wife. Mary has x+1 children by her first husband. They marry and have children of their own. The whole family has 24 children. Assuming the two children of same parents do not fight, then find the maximum possible number of fights that can take place

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Important Questions on Application of Derivatives

MEDIUM
If x=-1 and x=2 are extreme points of fx=αlogx+βx2+x, then 
HARD
If a right circular cone, having maximum volume, is inscribed in a sphere of radius 3 cm, then the curved surface area (in cm2) of this cone is :
HARD
Let k and K be the minimum and the maximum values of the function fx=1+x0.61+x0.6 in 0, 1, respectively, then the ordered pair (k, K) is equal to:
MEDIUM
The maximum volume in cubic m of the right circular cone having slant height 3 m is:
EASY
If fx=xx2+1 is an increasing function then the value of x lies in
HARD
The maximum area of a rectangle that can be inscribed in a circle of radius 2 units is
MEDIUM
From the top of a 64 metres high tower, a stone is thrown upwards vertically with the velocity of 48 m/s. The greatest height (in metres) attained by the stone, assuming the value of the gravitational acceleration g=32 m/s2, is:
EASY
The maximum value of the function fx=2x3-15x2+36x+4 is attained at
HARD
The maximum area (in sq. units) of a rectangle having its base on the x- axis and its other two vertices on the parabola, y=12-x2 such that the rectangle lies inside the parabola, is :
HARD
If the function f given by fx=x3-3a-2x2+3ax+7, for some aR is increasing in 0, 1 and decreasing in 1, 5, then a root of the equation, fx-14x-12=0, x1 is :
MEDIUM
Twenty meters of wire is available for fencing off a flower-bed in the form of a circular sector. Then the maximum area (in sq. m) of the flower-bed, is:
MEDIUM
The difference between the greatest and the least value of fx=2sinx+sin2x, x0,3π2 is
HARD
The maximum value of fx=logxx (x0,x1) is
HARD
A solid hemisphere is mounted on a solid cylinder, both having equal radii. If the whole solid is to have a fixed surface area and the maximum possible volume, then the ratio of the height of the cylinder to the common radius is
EASY
Let M and m be respectively the absolute maximum and the absolute minimum values of the function, fx=2x3-9x2+12x+5 in the interval [0,3] . Then M-m is equal to
HARD
Among all sectors of a fixed perimeter, choose the one with maximum area. Then the angle at the center of this sector (i.e., the angle between the bounding radii) is-
HARD
Let fx=α x2-2+1x where α is a real constant. The smallest α for which fx0 for all x>0 is-
HARD
The maximum value of fx=x4+x+x2 on [-1, 1] is
MEDIUM
The least value of αR for which, 4αx2+1x 1, for all x>0, is 
EASY
If at x=1, the function x4-62x2+ax+9 attains its local maximum value, on the interval 0,2, then the value of a is