Kirchhoff's junction rule is a reflection of

In the circuit element given here, if the potential at point $B, V_B=0$, then the potentials of $A$ and $D$ are given as

The magnitude of $i$ in ampere unit is

If in the circuit shown below, the internal resistance of the battery is $1.5 \mathrm{\Omega }$ and $V_P$ and $V_Q$ are the potentials at $P$ and $Q$, respectively. What is the potential difference between the points $P$ and $Q$?

In the circuit shown below $E_1=4.0 \mathrm{V}, R_1=2 \mathrm{\Omega }, E_2=6.0 \mathrm{V}, R_2=4 \mathrm{\Omega }$  and $R_3=2 \mathrm{\Omega }$. The current $I_1$ is

Consider the circuits shown in the figure. Both the circuits are taking the same current from battery but current through $R$ in the second circuit is $\frac{1}{10}$th of current through $R$ in the first circuit. If $R$ is $11 \mathrm{\Omega }$, then the value of $R_1$ is

Current through the wire $XY$ of the circuit shown is

In the circuit of the adjoining figure, the current through $12 \mathrm{\Omega }$ resistor will be

The circuit is shown in the following figure. The potential at points $A, B, C, D$ and $O$ are given. The currents in the resistances $R_1, R_2$ and $R_3$ are in the ratio of $4:2:1$ What is the ratio of resistances $R_1, R_2, R_3$ and $R_4$?