
Least count of two screw gauges is same then.

Important Questions on Experimental Physics

The readings of the main scale and the circular scale, for a thin sheet, are and respectively, the thickness of this sheet is:

In an experiment to find out the diameter of wire using screw gauge, the following observation were noted:
(a) Screw moves on main scale in one complete rotation
(b) Total divisions on circular scale
(c) Main scale reading is
(d) division of circular scale is in the pitch line
(e) Instrument has negative error Then the diameter of wire is :



There are two vernier calipers both of which have divided into equal divisions on the main scale. The Vernier scale of one of the calipers has equal divisions that correspond to main scale divisions. The Vernier scale of the other caliper has equal divisions that correspond to main scale divisions. The readings of the two calipers are shown in the figure. The measured values (in ) by calipers and respectively, are

[Screw gauge has divisions on the circular scale]



If in five complete rotations of the circular scale, the distance travelled on the main scale of the screw gauge is and there are total divisions on a circular scale, then the least count is
Least Count
In the light of the above statements, choose the most appropriate answer from the options given below.

S.No. | MS (cm) | VS divisions |
1. | 0.5 | 8 |
2. | 0.5 | 4 |
3. | 0.5 | 6 |
If the zero error is - 0.03 cm, then mean corrected diameter is:







Student and student used two screw gauges of equal pitch and equal circular divisions to measure the radius of a given wire. The actual value of the radius of the wire is . The absolute value of the difference between the final circular scale readings observed by the students and is _______.
[Figure shows position of reference when jaws of screw gauge are closed]
Given pitch .



