Let $AX=B$ be a system of $3$ linear equations with $3$-unknowns. Let $X_1$ and $X_2$ be its two distinct solutions. If the combination $a{X}_1+b{X}_2$ is a solution of $AX=B$; where $a, b$ are real numbers, then which one of the following is correct?

Directions: Each of the following sentences in this section has a blank space and four words or group of words given after the sentence. Select the word or group of words you consider most appropriate for the blank space and indicate your response on the Answer Sheet accordingly.

Every rash driver becomes a ____ killer.

The number of real values of $\lambda$ for which the system of linear equations, $2x+4y-\lambda z=0$, $4x+\lambda y+2z=0$ and $\lambda x+2y+2z=0$, has infinitely many solutions, is:

An ordered pair $\left(\alpha , \beta \right)$ for which the system of linear equations
$\left(1+\alpha \right)x+\beta y+z=2$
$\alpha x+\left(1+\beta \right)y+z=3$
$\alpha x+\beta y+2z=2$

has a unique solution, is :

If the system of linear equations

$x+ky+3z=0$
$3x+ky-2z=0$
$2x+4y-3z=0$

has a non-zero solution $\left(x, y, z\right),$ then $\frac{xz}{y^2}$ is equal to:

Two sentences are given below and you are required to find the correct sentence which combines both the sentences.

Which is the correct combination of the given two sentences?

He is too tired. He could not stand.

In the following sentence, a blank space with four options is given. Select whichever preposition or determiner you consider the most appropriate for the blank space.

These are the good rules to live _____.

If $a, b, c$  are non - zero real numbers and if the system of equations

$\left(a-1\right)x=y+z$

$\left(b-1\right)y=x+z$

$\left(c-1\right)z=x+y$

has a non - trivial solution, then $ab+bc+ca$  equals :

Let $\lambda$ be a real number for which the system of linear equations

$x+y+z=6,$

$4x+\lambda y-\lambda z=\lambda -2$ and

$3x+2y-4z=-5$

has infinitely many solutions. Then $\lambda$ is a root of the quadratic equation: