EASY
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IMPORTANT
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Let P be the plane, which contains the line of intersection of the planes, x+y+z-6=0 and 2x+3y+z+5=0 and it is perpendicular to the xy-plane. Then the distance of the point 0, 0, 256 from P is equal to:

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Important Questions on Three Dimensional Geometry

HARD
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IMPORTANT
The equation of the line passing through -4, 3, 1, parallel to the plane x+2y-z-5=0 and intersecting the line x + 1-3=y-32=z-2-1 is
MEDIUM
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IMPORTANT
The plane through the intersection of the planes x+y+z=1 and 2x+3y-z+4=0 and parallel to y- axis also passes through the point
MEDIUM
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IMPORTANT
If the lines x=ay+b,z=cy+d and x=az+b,  y=c  z+d are perpendicular, then
HARD
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IMPORTANT
The equation of the plane containing the straight line x2=y3=z4 and perpendicular to the plane containing the straight lines x3=y4=z2 and x4=y2=z3 is:
MEDIUM
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IMPORTANT
The length of the perpendicular from the point (2,-1, 4) on the straight line x+3 10=y-2-7=z1 is
MEDIUM
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IMPORTANT
The equation of a plane containing the line of intersection of the planes 2x-y-4=0 and y+2z-4=0 and passing through the point 1,1,0 is
MEDIUM
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IMPORTANT
The vector equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 which is perpendicular to the plane x-y+z=0 is
MEDIUM
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IMPORTANT
If a point R4,y,z lies on the line segment joining the points P2,-3,4  and Q8,0,10, then the distance of R from the origin is