EASY
Earn 100

Let the first term a and the common ratio r of a geometric progression be positive integers. If the sum of squares of its first three terms is 33033, then the sum of these three terms is equal to

53.33% studentsanswered this correctly

Important Questions on Arithmetic and Geometric Progression

HARD

If m is the A.M. of two distinct real numbers I and n I, n>1  and G1, G2 and G3 are three geometric means between I and n, then G14+2G24+G34 equals

EASY
The product of three consecutive terms of a G.P. is 512. If 4 is added to each of the first and the second of these terms, the three terms now form an A.P., then the sum of the original three terms of the given G.P. is :
MEDIUM
Let a1,a2,a3,, be a G.P. such that a1<0,a1+a2=4 and a3+a4=16. If i=19ai=4λ, then λ is equal to
MEDIUM
Let α and β be the roots of x2-3x+p=0 and γ and δ be the roots of x2-6x+q=0. If α,β,γ,δ from a geometric progression. Then ratio (2 q+p):(2 q-p) is
MEDIUM
Let a, b and c be the 7th, 11th and 13th terms respectively of a non-constant A.P. If these are also the three consecutive terms of a G.P., then ac is equal to:
HARD

The sum of the first three terms of G.P is S and their products is 27. Then all such S lie in

HARD
Let an be the nth term of a G.P. of positive terms. If n=1100a2n+1=200 and n=1100a2n=100, then n=1200an is equal to:
HARD
If a=1+2+4+ up to n terms, b=1+3+9+ up to n terms and c=1+5+25+ up to n terms, then Δ=a2b4c2222n3n5n=
EASY
Let a1,a2,..a10 be a G.P. If a3a1=25, then a9a5  equals:
 
MEDIUM
Let a, b and c be in G.P. with common ratio r, where a0 and 0<r12. If 3a, 7b and 15c are the first three terms of an A.P., then the 4th term of this A.P. is :
HARD
Let a, b, c, d and p be non-zero distinct real numbers such that a2+b2+c2p2-2(ab+bc+cd)p+b2+c2+d2=0. Then
MEDIUM
If the 2nd, 5th and 9th terms of a non-constant arithmetic progression are in geometric progression, then the common ratio of this geometric progression is
EASY
If a1x=b1y=c1z and a, b, c are in G.P., then x, y, z  will be in
EASY
The third term of a G.P. is 9. The product of its first five terms is 
EASY
Let a, b & c be in A.P. with a common difference d. Then e1c, ebac, e1a are in
MEDIUM
If the fifth term of a G.P. is 2. Then the product of its first 9 terms is
MEDIUM
The three sides of a right angled triangle are in GP (geometric progression). If the two acute angles be α and β, then tan α and tan β are
MEDIUM
If α,β and γ are three consecutive terms of a non-constant G.P. Such that the equations αx2+2βx+γ=0 and x2+x-1=0 have a common root, then αβ+γ is equal to:
MEDIUM
If three distinct numbers a, b, c are in G.P. and the equations ax2+2bx+c=0 and dx2+2ex+f=0 have a common root, then which one of the following statements is correct?
MEDIUM
The sum of the 3rd and the 4th terms of a G.P. is 60 and the product of its first three terms is 1000. If the first term of this G.P. is positive, then its 7th term is: