Light of frequency $1.5$ times the threshold frequency is incident on a photosensitive material, photoelectric current is emitted. If the frequency of light is halved and intensity is doubled, the photoelectric current becomes

The following graph represents the variation of photo current with anode potential for a metal surface. Here $I_1, I_2$ and $I_3$ represents intensities and ${\gamma }_1,{\gamma }_2,{\gamma }_3$ represents frequency for curves $1, 2$ and $3$ respectively, then

The photoelectric threshold for a certain metal surface is $360 \mathrm{Å}$. If the metal surface is irradiated by a wavelength of $1100 \mathrm{Å}$, the kinetic energy of the emitted photoelectrons is

Given figure shows few data points in a photo-electric effect experiment for a certain metal. The minimum energy for ejection of electrons from its surface is: (Planck's constant $\mathrm{h}=6.62\times {10}^{–34}\text{ J.s}$)

The work function of three photosensitive materials used to build photoelectric devices are given as : Sodium $(2.75 \mathrm{eV}),$ copper $(4.65 \mathrm{eV})$ and gold $(5.1 \mathrm{eV}).$ Which of the following statements is correct. (The frequency of visible light lies in the range $4\times {10}^{14} \mathrm{Hz}$ to $8\times {10}^{14} \mathrm{Hz}) ?$