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Light of wavelength 6000  is incident on a thin glass plate of refractive index 1.5 such that the angle of refraction on the plate is 60°. Calculate the smallest thickness of plate which will make it appear dark by reflection.

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Important Questions on Wave Optics

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Light is incident on a glass plate (μ=1.5) such that the angle of refraction is 60°. A dark band is observed corresponding to the wavelength of 6000 . If the thickness of glass plate is 1.2 ×10-3 mm, calculate the order of the interference band.
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The direction of the second maximum in the Fraunhofer diffraction pattern at a single slit is given by (a is the width of the slit),

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The angular width θ of central maximum of a diffraction pattern of a single slit does not depend upon,
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In the diffraction pattern of a single slit aperture, the width of the central fringe compared to the widths of the other fringes is,
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The central fringe obtained in diffraction pattern due to a single slit,

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In a single-slit diffraction pattern, if the light source used is of less wavelength than the previous one, the width of the central fringe would be,
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In the laboratory, diffraction of light by a single-slit is being observed. If the slit is made slightly narrow, then diffraction pattern will be,
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Find the half angular width of the central bright maximum in the Fraunhofer diffraction pattern of a slit of width 12 × 10-5 cm when the slit is illuminated by monochromatic light of wavelength 6000 .