Liquid filled in the container has density $5 {\mathrm{kgm}}^{-3}$. If the container is moving horizontally with acceleration $a=$ $2 {\mathrm{ms}}^{-2}$ then pressure difference between two points $A$ and $B$, which are at the same level with separation between them $50\mathrm{cm}$, will be

 

When at rest, a liquid stands at the same level in the tube shown in figure. But as indicated a height difference $h$ occurs when the system is given an acceleration a towards the right. Then $h$ is equal to

A body having volume $V$ is floating, fully submerged in a liquid of density $\rho$. If the container starts moving upward with constant acceleration $\frac{g}{3}$ then the buoyant force acting on the body will become

Find the pressure difference between $A$ and $B$.

If container is accelerated towards right with acceleration $a=g$. Find pressure at $A$.

It is desired to design an air plane with a "lift" of $1000 \mathrm{~N}$ per square meter of wing area. If the velocity of streamline flow past the lower wing surface is $100 \mathrm{~m} / \mathrm{s}$, then the required velocity over the upper surface is (given density of air is $1.3 \mathrm{~kg} \mathrm{~m}^{-3}$ )

Equal volume of two immiscible liquids of densities $\rho$ and $2\rho$ are filled in a vessel as shown in figure. Two small holes are punched at depth $\frac{h}{2}$ and $\frac{3h}{2}$ from the surface of lighter liquid. If $v_1$ and $v_2$ are the velocities of efflux at these two holes, then $\frac{v_1}{v_2}$ is