Work out the binding energy per nucleon (in MeV per nucleon) for the isotope Fe 26 56 . Given the masses: Fe 56 = 55 . 93494 amu , neutron = 1 . 008665 amu , proton = 1 . 00783 amu , electron = 0 . 00054859 amu .

Binding energy per nucleon = B . E . B . E . = ∆ mc 2 . . . . . . 1 ∆ m = n p m p + n n m n - m Fe ∆ m = 26 × 1 . 00783 + 30 × 1 . 008665 - 55 . 93494 ∆ m = 0 . 5285 Now, with equation 1 , B . E . / nucleon = ∆ mc 2 A = 0 . 5285 × 3 × 10 8 2 56 = 0 . 0094 c 2 amu = 0 . 0094 × 931 = 8 . 76 MeV 1 amu = 931 MeV / c 2 So, according to the above solution, by using formula for finding binding energy per nucleon, it will be equal to 8 . 76 MeV per nucleon.

E M B I B E

Concise Inorganic Chemistry>Chapter 30 - The Atomic Nucleus>Exercise 1>Q 23

MEDIUM

JEE Advanced

IMPORTANT

Earn 100

List the uses of radioactive isotopes.

Important Questions on The Atomic Nucleus

HARD

JEE Advanced

IMPORTANT

Concise Inorganic Chemistry>Chapter 30 - The Atomic Nucleus>Exercise 1>Q 1

What is the nature of the binding forces in atomic nuclei? How does the average binding energy per nucleon vary with the atomic number of the element?