Look at the figure below.

Areas of which of these triangles are equal?

$ABCD$ is a parallelogram where $AB=8 \mathrm{cm}, AD=4 \mathrm{cm}$ and $\angle B=120°$. What is the area of $ABCD$?

In the given figure, $ABCD$ is a parallelogram in which $AD=21 \mathrm{cm}, DH=18 \mathrm{cm}$ and $DK=27 \mathrm{cm}$. The perimeter of the parallelogram is

In the given figure, $\mathrm{ABCD}$ is a parallelogram in which $\mathrm{AD}=21 \mathrm{cm}, \mathrm{DH}=18 \mathrm{cm}$ and $\mathrm{DK}=27 \mathrm{cm}$. The length of side $\mathrm{AB}$ is

$ABCD$ is a parallelogram, $\mathrm{DL}\perp \mathrm{AB}$. If $\mathrm{AB}=20 \mathrm{cm}, \mathrm{AD}=13 \mathrm{cm}$ and area of the parallelogram is $100 {\mathrm{cm}}^2$, find $\mathrm{AL}$.

In given figure, $ABCD$ is a parallelogram of area $144 {\mathrm{cm}}^2$, the value of $x$ is

In a parallelogram $ABCD$, $AB=18 \mathrm{cm}$, $BC=12 cm$, $AL\perp DC$ and $AM\perp BC$. If $AL=6.4 cm$, find the length of $AM$.