Explain [ Co ( NH 3 ) 6 ] 3 + is an inner orbital complex whereas [ Ni ( NH 3 ) 6 ] 2 + is an outer orbital complex.

In the presence of NH 3 , the 3 d electrons pair up leaving two d orbitals empty to be involved in d 2 sp 3 hybridisation forming inner orbital complex in case of [ Co ( NH 3 ) 6 ] 3 + . The ligand acts as the strong ligand in the cobalt complex. In Ni ( NH 3 ) 6 2 + , Ni is in + 2 oxidation state and has d 8 configuration, the hybridisation involved is sp 3 d 2 forming outer orbital complex. Here, the ligand acts as a weak ligand.

E M B I B E

Chemistry Crash Course (Based on Revised Syllabus-2023)>Chapter 5 - Coordination Compounds>Exercise>Q 15

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IMPORTANT

Earn 100

Metal in the chlorophyll is:

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Important Questions on Coordination Compounds

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Chemistry Crash Course (Based on Revised Syllabus-2023)>Chapter 5 - Coordination Compounds>Exercise>Q 16

Mohr's salt is

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Chemistry Crash Course (Based on Revised Syllabus-2023)>Chapter 5 - Coordination Compounds>Exercise>Q 17

Which complex cannot ionize in solution?

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Chemistry Crash Course (Based on Revised Syllabus-2023)>Chapter 5 - Coordination Compounds>Exercise>Q 18

A chelating ligand has two or more than two donor atoms to bind to a single metal ion. Which of the following is not a chelating ligand?

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Chemistry Crash Course (Based on Revised Syllabus-2023)>Chapter 5 - Coordination Compounds>Exercise>Q 19

The correct order of the stoichiometries of

AgCl

formed when

{AgNO}_{3}

is treated in excess with the complexes:

{CoCl}_{3} . 6 {NH}_{3}, {CoCl}_{3} . 5 {NH}_{3}, {CoCl}_{3} . 4 {NH}_{3}

, respectively, is:

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Chemistry Crash Course (Based on Revised Syllabus-2023)>Chapter 5 - Coordination Compounds>Exercise>Q 20

If an excess of ${AgNO}_{3}$ solution is added to $100 mL$ of $0.024 M$ solution of dichloridobis (ethylenediamine) cobalt $(III)$ chloride, how many moles of $AgCl$ are precipitated?

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Chemistry Crash Course (Based on Revised Syllabus-2023)>Chapter 5 - Coordination Compounds>Exercise>Q 21

A solution containing $0.319 g$ of ${CrCl}_{3} \cdot 6 H_{2} O$ was passed through cation-exchange resin and the acid coming out of the exchange resin consumed $28.5 mL$ of $0.125 M NaOH$ solution. The formula of the complex is: