Molar ionic conductivities of two-bivalent electrolytes ${\mathrm{x}}^{2+}$ and ${\mathrm{y}}^{2-}$ are $57$ and $73$, respectively. The molar conductivity of the solution formed by them will be

Standard electrode potentials of two half cells are given as 

${\mathrm{Zn}}^{2+}|\mathrm{Zn}=-0.76 \mathrm{V};\mathrm{Ag}|\mathrm{Ag}=0.80 \mathrm{V}$

The $\mathrm{emf}$ of the cell $\mathrm{Zn}\left|{\mathrm{Zn}}^{2+}\right(1\mathrm{M})\Vert {\mathrm{Ag}}^{+}|\mathrm{Ag}\left(1\mathrm{M}\right)$ will be

In the electrochemical reaction $2{\mathrm{Fe}}^{3+}+\mathrm{Zn}⟶{\mathrm{Zn}}^{2+}+2{\mathrm{Fe}}^{2+},$ increasing the concentration of ${\mathrm{Fe}}^{2+}$