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NH4Cl crystallizes in a body-centered cubic type lattice with a unit cell edge length of 387pm. The distance between the oppositively charged ions in the lattice is

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Important Questions on Solid State

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The density of a pure substance 'A' whose atoms are packed in a cubic-close packed arrangement is 1 g cc-1. If B atoms can occupy tetrahedral void and all the tetrahedral voids are occupied by 'B' atoms, what is the density of resulting solid in g cc-1? [Atomic mass (A)=30 g mol-1 and atomic mass (B)=50 g mol-1].

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In the body-centered cubic unit cell \& face centered cubic unit cell, the radius of atom in terms of edge lengh(a) of the unit cell is respectively:
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In FCC unit cell, what fraction of edge length is not covered by atoms?
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Diamond structure can be considered as ZnS (Zinc blend) structure in which each Zn2+ in alternate tetrahedral void and S2 - in cubic close pack arrangement is replaced by one carbon atom. If C-C covalent bond length in diamond is 1.5A°, what is the edge length of diamond unit cell (z=8).
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Copper metal crystallizes in FCC lattice. Edge length of unit cell is 362pm. The radius of largest atom that can fit into the voids of copper lattice without disturbing it.
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Packing fraction in 2-D hexagonal arrangement is
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A solid is formed and it has three types of atoms X, Y and Z. X forms a fcc lattice with Y atoms occupying all tetrahedral voids and Z atoms occupying half of octahedral voids. The formula of solid is
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A compound XY crystallizes in BCC lattice with unit cell edge length of 480pm. If the radius of Y- is 225pm, then the radius of X+ is :-