EASY
Earn 100

Name different types of oscillations.

Important Questions on Oscillations

EASY
The displacement of a damped harmonic oscillator is given by xt=e-0.1tcos10πt+φ. Here t is in seconds. The time taken for its amplitude of vibration to drop to half of its initial value is close to:
HARD

A pendulum with the time period of 1 s is losing energy due to damping. At a certain time, its energy is 45 J. If after completing 15 oscillations its energy has become 15 J, then its damping constant (in s-1) will be

EASY
Why does the amplitude of a vibrating body continuously decrease during damped vibrations?
EASY
A block of mass 0.1 kg is connected to an elastic spring of spring constant 640 N m-1 and oscillates in a damping medium of damping constant 10-2 kg s-1 . The system dissipates its energy gradually. The time taken for its mechanical energy of vibration to drop to half of its initial value, is closest to-
MEDIUM
The amplitude of a damped oscillator becomes half in one minute. The amplitude after 3 minutes will be 1x times the original. Then x is
MEDIUM
A damped harmonic oscillator has a frequency of 5 oscillations per second. The amplitude drops to half its value for every 10 oscillations. The time it will take to drop to 11000 of the original amplitude is close to:
EASY
Instantaneous power delivered to a damped harmonic oscillator (natural frequency is ω0), by an external periodic force (driving frequency ω) under steady state conditions is
EASY
The amplitude of a mass-spring system, which is executing simple harmonic motion decreases with time. If mass =500 g, Decay constant =20 g s-1 then how much time is required for the amplitude of the system to drop to half of its initial value? ln2=0.693
EASY

The amplitude of a simple pendulum, oscillating in air with a small spherical bob, decreases from 10 cm to 8 cm in 40 seconds. Assuming that Stokes law is valid, and ratio of the coefficient of viscosity of air to that of carbon dioxide is 1.3, the time in which amplitude of this pendulum will reduce from 10 cm to 5 cm in carbondioxide will be close to (ln 5 = 1.601, ln 2 = 0.693).

EASY
A block of mass 1 kg attached to a spring is made to oscillate with an initial amplitude of 12 cm. After 2 minutes the amplitude decreases to 6 cm. Determine the value of the damping constant for this motion. (take ln2=0.693 )
EASY
Two pendulums C and D are suspended from a wire as shown in the given figure. Pendulum C is made to oscillate by displacing it from its mean position. It is seen that D also starts oscillating. Name the type of oscillation, C will execute.
Question Image
EASY

Two pendulums C and D are suspended from a wire as shown in the given figure. Pendulum C is made to oscillate by displacing it from its mean position. It is seen that D also starts oscillating. If the length of D is made equal to C, then what difference will you notice in the oscillations of D

Question Image

MEDIUM
The amplitude of a damped oscillator decreases to 0.9 times its original magnitude in 5s. In another 10s it will decrease to α times its original magnitude, where α equals :
EASY
In the following a statement of Assertion is followed by a statement of Reason.

Assertion: In damped oscillations, the oscillator experiences both conservative and non-conservative forces.

Reason: In damped oscillations mechanical energy of oscillator decreases with time.
MEDIUM
The displacement of a damped harmonic oscillator is given by x(t)=e-0.1tcos(10πt+φ). Here t is in seconds. What will be time taken for its amplitude of vibration to drop to half of its initial value is close to ?
HARD
You are riding in an automobile of mass 3000 kg. Assuming that you are examining the oscillation characteristics of its suspension system. The suspension sags 15 cm when the entire automobile is placed on it. Also, the amplitude of oscillation decreases by 50% during one complete oscillation. Estimate the values of (a) the spring constant k and (b) the damping constant b for the spring and shock absorber system of one wheel, assuming that each wheel supports 750 kg.
MEDIUM
A block of mass 200 g is executing SHM under the influence of a spring of spring constant k=90 N m-1 and a damping constant b=40 g s-1. The time elapsed for its amplitude to drop to half of its initial value is (Given, ln12=-0.693)
MEDIUM
A simple pendulum after some time becomes slow in motion and finally stops due to
EASY
Which of the following displacement-time graphs represent damped harmonic oscillation?
HARD
The amplitude of damped oscillator becomes 12 in 2 s. Its amplitude after 6 is 1n times the original. Then n is equal to