A compound X (having vinegar-like smell) when treated with ethanol in the presence of the acid, Z gives a compound Y which has a fruity smell. The reaction is C 2 H 5 OH + X → Z Y + H 2 O . Identify Y and Z .

The compound X is CH 3 COOH (acetic acid), Y is CH 3 COOC 2 H 5 (ethyl ethanoate) and Z is concentrated sulphuric acid. C 2 H 5 OH + CH 3 COOH → Conc . H 2 SO 4 CH 3 COOC 2 H 5 + H 2 O

A compound X (having vinegar-like smell) when treated with ethanol in the presence of the acid Z , gives a compound Y which has a fruity smell. The reaction is: C 2 H 5 OH + X → Z Y + H 2 O Name the above reaction.

The above reaction is an esterification reaction. In this reaction, ethanol reacts with acetic acid to form an ester that is ethyl ethanoate is formed as a product. C 2 H 5 OH Ethanol + CH 3 COOH Acetic acid → Conc . H 2 SO 4 CH 3 COOC 2 H 5 Ethyl ethanoate + H 2 O

Name the following organic compound: The compound with 3 carbon atoms whose functional group is a carboxyl.

A carboxyl group consists of a carbonyl group with a hydroxyl group attached to the same carbon atom. Propanoic acid is the compound with 3 carbon atoms whose functional group is a carboxyl having the formula CH 3 CH 2 COOH .