Nitrobenzene and ${\mathrm{CH}}_3\mathrm{Cl}$ in presence of anhydrous ${\mathrm{AlCl}}_3$ gives:

  ${\mathrm{CH}}_3{\mathrm{CH}}_2\mathrm{Cl}$     $\frac{\text{ Anhydrous }}{{\mathrm{AlCl}}_3}\to$ product.

Product is:

${\mathrm{C}}_6{\mathrm{H}}_6+{\mathrm{C}}_2{\mathrm{H}}_5-\mathrm{CO}-\mathrm{Cl} \stackrel{\mathrm{Anhydrous} {\mathrm{AlCl}}_3}{\to }\mathrm{X}$

$\mathrm{X}$ is :

Identify the product.