Nitroglycerine is used as an explosive. The equation for the explosive reaction is: 4 C 3 H 5 ( NO 3 ) 3 → 12 CO 2 + 10 H 2 O + 6 N 2 + O 2 (Atomic mass of C = 12, H = 1, N = 14, O = 16) How many moles of gas molecules are obtained from 1 mole of nitroglycerine.

4 moles of nitroglycerine give 19 moles of gas molecules. 1 mole of nitroglycerine gives = 19 4 = 4 . 75 moles Hence, 1 mole of nitroglycerine produces 4.75 moles of gas. The mole is the base unit of the amount of substance in the International Unit of System of Units (SI). It is defined as exactly 6 . 022 × 10 23 elementary particles, which may be atoms, molecules, ions, or electrons.

Nitroglycerine is used as an explosive. The equation for the explosive reaction is: 4 C 3 H 5 ( NO 3 ) 3 → 12 CO 2 + 10 H 2 O + 6 N 2 + O 2 (Atomic mass of C = 12, H = 1, N = 14, O = 16) How many moles of gas molecules are obtained from 1 mole of nitroglycerine.

4 moles of nitroglycerine give 19 moles of gas molecules. 1 mole of nitroglycerine gives = 19 4 = 4 . 75 moles Hence, 1 mole of nitroglycerine produces 4.75 moles of gas. The mole is the base unit of the amount of substance in the International Unit of System of Units (SI). It is defined as exactly 6 . 022 × 10 23 elementary particles, which may be atoms, molecules, ions, or electrons.

Nitroglycerine is used as an explosive. The equation for the explosive reaction is: 4 C 3 H 5 ( NO 3 ) 3 → 12 CO 2 + 10 H 2 O + 6 N 2 + O 2 (Atomic mass of C = 12, H = 1, N = 14, O = 16) What is the mass of 1 mole of glycerine?

Mass of 1 mole of nitroglycerine [ C 3 H 5 ( N O 3 ) 3 ] = C ( 3 × 12 ) + H ( 1 × 5 ) + N ( 3 × 14 ) + O ( 9 × 16 ) = C ( 36 ) + H ( 5 ) + N ( 42 ) + O ( 144 ) = 227 g Mass of 1 mole of nitroglycerine is 227g. The total sum of the masses of the atoms of elements present in a molecule is termed as molecular mass.

Nitroglycerine is used as an explosive. The equation for the explosive reaction is: 4 C 3 H 5 ( NO 3 ) 3 → 12 CO 2 + 10 H 2 O + 6 N 2 + O 2 (Atomic mass of C = 12, H = 1, N = 14, O = 16) What is the mass of 1 mole of glycerine?

Mass of 1 mole of nitroglycerine [ C 3 H 5 ( N O 3 ) 3 ] = C ( 3 × 12 ) + H ( 1 × 5 ) + N ( 3 × 14 ) + O ( 9 × 16 ) = C ( 36 ) + H ( 5 ) + N ( 42 ) + O ( 144 ) = 227 g Mass of 1 mole of nitroglycerine is 227g. The total sum of the masses of the atoms of elements present in a molecule is termed as molecular mass.

Nitroglycerine is used as an explosive. The equation for the explosive reaction is: 4 C 3 H 5 ( NO 3 ) 3 → 12 CO 2 + 10 H 2 O + 6 N 2 + O 2 ( l ) ( g ) ( l ) ( g ) ( g ) Atomic mass of C = 12, H = 1, N = 14, O = 16) How many moles does the equation show for gas molecules produced?

The number of moles of nitroglycerine is 4. The number of moles of gas produced by 4 moles of nitroglycerin are- The number of gas molecules = 12 CO 2 + 6 N 2 + O 2 = 12 + 6 + 1 = 19 moles The mole is the base unit of the amount of substance in the International Unit of System of Units (SI). It is defined as exactly 6 . 022 × 10 23 elementary particles, which may be atoms, molecules, ions, or electrons.

Nitroglycerine is used as an explosive. The equation for the explosive reaction is: 4 C 3 H 5 ( NO 3 ) 3 → 12 CO 2 + 10 H 2 O + 6 N 2 + O 2 ( l ) ( g ) ( l ) ( g ) ( g ) (Atomic mass of C = 12, H = 1, N = 14, O = 16) How many moles does the equation show for nitroglycerine?

4 C 3 H 5 ( NO 3 ) 3 → 12 CO 2 + 10 H 2 O + 6 N 2 + O 2 The number of moles is shown by nitroglycerine = 4 moles . The mole is the base unit of the amount of substance in the International Unit of System of Units (SI). It is defined as exactly 6 . 022 × 10 23 elementary particles, which may be atoms, molecules, ions, or electrons.

Identify and correct the mistake, if any. The molar volume of gas at STP is 22 . 4 cm 3

The molar volume of gas at STP is equal to 22 . 4 L or 22400 cm 3 . The molar volume of a gas is defined as the volume occupied by one mole of gas at STP(standard temperature and pressure). It has been found that one mole of any gas occupies a volume of 22.4 L at STP.

Identify and correct the mistake, if any. 2 × R . M . M = V . D .

R . M . M = 2 × V . D . Vapour density is the density of vapour in relation to that of hydrogen. It may be defined as the mass of a certain volume of a substance divided by the mass of the same volume of hydrogen.

Find how many moles of atoms are there in: 32 g of sulphur.

Number of moles = Mass of sulphur Atomic mass of sulphur Given, the mass of sulphur = 32 g The atomic mass of sulphur = 32 Number of moles of sulphur = 32 32 = 1 A mole is defined as the amount of a substance that contains exactly 6 . 022 × ' 0 23 elementary entities of the given substance.

Find how many moles of atoms are there in: 14 g of lithium.

Number of moles = Mass of lithium Atomic mass of lithium Given the mass of lithium = 14 g The atomic mass of lithium = 7 Number of moles of lithium = 14 7 = 2 A mole is defined as the amount of a substance that contains exactly 6 . 022 × 10 23 elementary entities of the given substance.

Find how many moles of atoms are there in: 40 g of calcium.

Number of moles = Given mass Molar mass Given, the mass of calcium (w)= 40 g The molar mass of calcium (M) = 40 g/mol Number of moles of calcium = w M = 40 40 mol = 1 A mole is defined as the amount of a substance that contains exactly 6 . 022 × 10 23 elementary entities of the given substance.