Match the C p C v ratio for ideal gases with different type of molecules: Molecule Type C p / C v (A) Monoatomic (I) 7 / 5 (B) Diatomic rigid molecules (II) 9 / 7 (C) Diatomic non-rigid molecules (III) 4 / 3 (D) Triatomic rigid molecules (IV) 5 / 3

(A) – (IV), (B) – (I), (C) – (II), (D) – (III)

(A) – (IV), (B) – (II), (C) – (I), (D) – (III)

(A) – (III), (B) – (IV), (C) – (II), (D) – (I)

(A) – (II), (B) – (III), (C) – (I), (D) – (IV)

The average kinetic energy of a molecule of the gas is

proportional to absolute temperature

dependent on the nature of the gas

The root mean square velocity of molecules of gas is

Proportional to square root of temperature T .

Proportional to square of temperature ( T 2 ).

Inversely proportional to square root of temperature ( 1 T ).

Proportional to temperature ( T ) .

Given below are two statements: Statement I : The temperature of a gas is - 73 ° C . When the gas is heated to 527 ° C , the root mean square speed of the molecules is doubled. Statement II : The product of pressure and volume of an ideal gas will be equal to translational kinetic energy of the molecules. In the light of the above statements, choose the correct answer from the options given below:

Statement I is true but Statement II is false

Both Statement I and Statement II are true

Both Statement I and Statement II are false

Statement I is false but Statement II is true

EASY

JEE Main

IMPORTANT

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On the basis of kinetic theory of gases, the gas exerts pressure because its molecules:

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Important Questions on Kinetic Theory of Gases

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 9 - Kinetic Theory of Gases>JEE Main - 24 Feb 2021 Shift 2>Q 21

The root-mean-square speed of molecules of a given mass of a gas at

27 ° C

and

1

atmosphere pressure is

200 m s^{- 1} .

The root-mean-square speed of molecules of the gas at

127 ° C

and

2

atmosphere pressure is

\frac{x}{\sqrt{3}} m s^{- 1} .

The value of

x

will be __________.

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 9 - Kinetic Theory of Gases>JEE Main - 25 Feb 2021 Shift 2>Q 22

Given below are two statements:

Statement I: In a diatomic molecule, the rotational energy at a given temperature obeys Maxwell's distribution.

Statement II : In a diatomic molecule, the rotational energy at a given temperature equals the translational kinetic energy for each molecule.

In the light of the above statements, choose the correct answer from the options given below:

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 9 - Kinetic Theory of Gases>JEE Main - 2 September 2020 Shift 1>Q 23

A gas mixture consists of

3

moles of oxygen and

5

moles of argon at temperature

T

. Assuming the gases to be ideal and the oxygen bond to be rigid, the total internal energy (in units of

R T

) of the mixutre is :

MEDIUM

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 9 - Kinetic Theory of Gases>JEE Main - 2 September 2020 Shift 2>Q 24

An ideal gas in a closed container is slowly heated. As its temperature increases, which of the following statements are true ?

(A) the mean free path of the molecules decreases

(B) the mean collision time between the molecules decreases.

(D) the mean collision time remains unchanged.

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 9 - Kinetic Theory of Gases>JEE Main - 3 September 2020 Shift 1>Q 25

Question Image

Consider a gas of triatomic molecules. The molecules are assumed to be triangular and made of massless rigid rods whose vertices are occupied by atoms. The internal energy of a mole of the gas at temperature T is:

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 9 - Kinetic Theory of Gases>JEE Main - 3 September 2020 Shift 2>Q 26

To raise the temperature of a certain mass of gas by

50 ° C

at a constant pressure,

160

calories of heat is required. When the same mass of gas is cooled by

100 ° C

at constant volume,

240

calories of heat is released. How many degrees of freedom does each molecule of this gas have (assume gas to be ideal)?

EASY

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 9 - Kinetic Theory of Gases>JEE Main - 4 September 2020 Shift 1>Q 27

Match the $\frac{C_{p}}{C_{v}}$ ratio for ideal gases with different type of molecules:

Molecule Type	$C_{p} / C_{v}$
(A) Monoatomic	(I) $7 / 5$
(B) Diatomic rigid molecules	(II) $9 / 7$
(C) Diatomic non-rigid molecules	(III) $4 / 3$
(D) Triatomic rigid molecules	(IV) $5 / 3$

HARD

JEE Main

IMPORTANT

EMBIBE CHAPTER WISE PREVIOUS YEAR PAPERS FOR PHYSICS>Chapter 9 - Kinetic Theory of Gases>JEE Main - 4 September 2020 Shift 1>Q 28

Particle

A

of mass

m_{A} = \frac{m}{2}

moving along the

x

-axis with velocity

v_{0}

collides elastically with another particle

B

at rest having mass

m_{B} = \frac{m}{3}

. If both the particles move along the

x

-axis after the collision, the change

∆ λ

in the wavelength of the particle

A

, in terms of its de-Broglie wavelength

(λ_{0})

before the collision is:

On the basis of kinetic theory of gases, the gas exerts pressure because its molecules:

Important Questions on Kinetic Theory of Gases

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