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Oxide of Cr and Mn is reduced by Al by following reaction:
Cr2O3 + Al Cr + Al2O3
MnO2 + Al Mn + Al2O3
If 2 mole of mixture of oxides of Cr and Mn requires 3 moles of Al for complete reduction, then moles of Cr form is:

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Important Questions on Some Basic Concepts of Chemistry
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[Given : Density of water in the droplet ]

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