PQRS is a cyclic quadrilateral and RS is a diameter. If $\angle SPQ = {140}^o\angle RSQ$ is equal to

In figure $PQ$, is a chord of a circle with centre $O$ and $PT$ is its tangent at $P$. if $\angle QPT=60°$, then $\angle PRQ$ is

In the figure, points $P,Q,R$ and $S$ lie on a circle. Then the values of $x$ and $y$ are respectively

The sum of pairs of opposite angles of a cyclic quadrilateral is

Write the quadrants in which the following points lie:

$\left(-4,7\right)$