EASY
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Polar satellites

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Important Questions on Gravitation

MEDIUM
Define binding energy and obtain an expression for binding energy of a satellite revolving in a circular orbit round the earth.
EASY
A satellite is launched to a distance r from the centre of the earth to have a circular orbit around the earth. Its orbital velocity to maintain this orbit is (mass of the earth as ME)
EASY
A person jumps from the 5th  storey of a building with load on his head. The weight experienced by him before reaching the earth will be
MEDIUM
Two satellites, A and B, have masses m and 2m respectively. A is in a circular orbit of radius R and B is in a circular orbit of radius 2R around the earth. The ratio of their kinetic energies, KAKB is:
MEDIUM
A spaceship orbits around a planet at a height of 20 km from its surface. Assuming that only gravitational field of the planet acts on the spaceship, what will be the number of complete revolutions made by the spaceship in 24 hours around the planet?
[Given: Mass of planet  =8×1022 kg ,
Radius of planet =2×106 m,
Gravitational constant  G=6.67×10-11 Nm2/kg2 ]
HARD
Two stars of masses 3×1031 kg each, and at distance 2×1011 m rotate in a plane about their common centre of mass O. A meteorite passes through O moving perpendicular to the star's rotation plane. In order to escape from the gravitational field of this double star, the minimum speed that meteorite should have at O is ( Take Gravitational constant G=6.67×10-11 N m2 kg-2 )
MEDIUM
Two satellites A and B are revolving with critical velocities vA and vB around the earth, in circular orbits of radii R and 2R respectively. The ratio vAvB is
EASY
A satellite S is moving in an elliptical orbit around the earth. The mass of the satellite is very small compared to the mass of the earth. Then,
HARD
The mass density of a spherical galaxy varies as Kr over a large distance r from its center. In that region, a small star is in a circular orbit of radius R. Then the period of revolution,T depends on R as:
EASY
A body is moving in a low circular orbit about a planet of mass M and radius R. The radius of the orbit can be taken to be R itself. Then the ratio of the speed of this body in the orbit to the escape velocity from the planet is: 
MEDIUM
The minimum number of geostationary satellites required for uninterrupted global coverage is
MEDIUM
A satellite is revolving in a circular orbit at a height h from the earth's surface (radius of earth R; h << R ). The minimum increase in its orbital velocity required, so that the satellite could escape from the earth's gravitational field, is close to (Neglect the effect of atmosphere.)
MEDIUM
The energy required to take a satellite to a height h above the Earth surface (radius of Earth =6.4×103 km ) is E1, and the kinetic energy required for the satellite to be in a circular orbit at this height is E2. The value of h for which E1 and E2 are equal, is
EASY

Which satellite is used for geographical survey?

EASY
A remote-sensing satellite of earth revolves in a circular orbit at a height of 0.25×106 m above the surface of earth. If earth's radius is 6.38×106 m and g=9.8 s-2, then the orbital speed of the satellite is:
EASY
The ratio of the binding energy of a satellite at rest on earth's surface to the binding energy of a satellite of same mass revolving around the earth at a height h above the earth's surface is (R= radius of the earth).
MEDIUM
What is the minimum energy required to launch a satellite of mass m from the surface of a planet of mass M and radius R in a circular orbit at an altitude of 2R ?
EASY
A planet is moving in a circular orbit. It completes 2 revolutions in 360 days. What is its angular frequency?
HARD
A test particle is moving in a circular orbit in the gravitational field produced by a mass density ρr=Kr2. Identify the current relation between the radius R of the particle’s orbit and its period T:
EASY
The relative uncertainty in the period of a satellite orbiting around the earth is 10-2 . If the relative uncertainty in the radius of the orbit is negligible, the relative uncertainty in the mass of the earth is: