Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 241

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Rain is falling vertically with a velocity of $3 {kmh}^{- 1} .$ A man walks in the rain with a velocity of $4 {kmh}^{- 1} .$ The rain drops will fall on the man with a velocity of

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Important Questions on Kinematics

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 242

To a stationary man, rain appears to be falling at an angle

30 °

with the vertical. As he starts moving with a speed of

0.5 {ms}^{- 1}

he finds that the rain is falling vertically. Then the speed of rain with respect to the moving man is

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 243

A man weighing

80 kg

stands on a weighing scale in a lift which is moving upwards with a uniform acceleration of

5 m s^{- 2} .

What would be the reading on the scale?

(g = 10 m s^{- 2})

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 244

A block is dragged on smooth plane with the help of a rope which moves with velocity $v .$ The horizontal velocity of the block is

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 246

A body of mass

0.1 kg

attains a velocity of

10 {m s}^{- 1}

in

0.1 s

. The force acting on the body is,

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 247

A lift is going up. The variation in the speed of the lift is as given in the graph. The height to which the lift takes the passenger is

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 248

Calculate the slope of the shown line

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 249

The speed

(v)

of a particle moving along a straight line is given by

v = t^{2} + 3 t - 4

, where

v

is in

m s^{- 1}

and

t

in

seconds

. Find time

t

at which the particle will momentarily come to rest.

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Alpha Question Bank for Medical: Physics>Chapter 4 - Kinematics>Exercise-1>Q 250

The displacement of a body at any time t after starting is given by

s = 15 t - 0.4 t^{2} .

The velocity of the body will be

7 {m s}^{- 1}

after time :