EASY
11th Assam Board
IMPORTANT
Earn 100

Read the statement below carefully, and state, with reasons, if it is true or false:

The instantaneous acceleration of the point of contact during rolling is zero.

Important Questions on Systems of Particles and Rotational Motion

EASY
11th Assam Board
IMPORTANT

Read the statement below carefully, and state, with reasons, if it is true or false:

For perfect rolling motion, work done against friction is zero.

EASY
11th Assam Board
IMPORTANT

Read the statement below carefully, and state, with reasons, if it is true or false:

A wheel moving down a perfectly frictionless inclined plane will undergo slipping (not rolling) motion.

HARD
11th Assam Board
IMPORTANT
Separation of Motion of a system of particles into motion of the centre of mass and motion about the centre of mass:
Show pi=pi'+miV
where pi is the momentum of the ith particle (of mass mi), pi'=mivi'. Note vi' is the velocity of the ith particle relative to the centre of mass and V is velocity of cenre of mass.
Also, prove using the definition of the centre of mass pi'=0
HARD
11th Assam Board
IMPORTANT

Separation of Motion of a system of particles into motion of the centre of mass and motion about the centre of mass:

Show K=K'+12MV2
where K is the total kinetic energy of the system of particles, K' is the total kinetic energy of the system when the particle velocities are taken with respect to the centre of mass and 12MV2 is the kinetic energy of the translation of the system as a whole (i.e. of the centre of mass motion of the system).

HARD
11th Assam Board
IMPORTANT

Separation of Motion of a system of particles into motion of the centre of mass and motion about the centre of mass:

Show L=L'+R×MV
where L'=Σri'×pi' is the angular momentum of the system about the centre of mass with velocities taken relative to the centre of mass. Remember ri'=ri-Rri is the position of ith particle with respect to origin and R and V is the position and velocity of centre of mass with respect to origin, respectively.

Note, L' and R×MV can be said to be angular momenta, respectively, about and of the centre of mass of the system of particles.
HARD
11th Assam Board
IMPORTANT

Separation of Motion of a system of particles into motion of the center of mass and motion about the center of mass:

Show dL'dt=Σri'×dp'dt
Further, show that
dL'dt=τext'
where τext' is the sum of all external torques acting on the system about the centre of mass. (Hint: Use the definition of centre of mass and third law of motion. Assume the internal forces between any two particles act along the line joining the particles.)