Simplify 28 - 22 - 7 + 24 ÷ 6 - 8 - 4 ¯

Given 28 - 22 - 7 + 24 ÷ 6 - 8 - 4 ¯ Rule: The rule involving both brackets and order of operations is called BODMAS. in a mathematical expression the operations are performed in the following order: first operation inside the bracket, then "of", division, multiplication, addition and subtraction. So, 28 - 22 - 7 + 24 ÷ 6 - 8 - 4 ¯ = 28 - 22 - 7 + 24 ÷ 6 - 4 = 28 - 22 - 7 + 24 ÷ 2 = 28 - 22 - 7 + 12 = 28 - 22 - 19 = 28 - 3 = 25

Simplify 28 - 22 - 7 + 24 ÷ 6 - 8 - 4 ¯

Given 28 - 22 - 7 + 24 ÷ 6 - 8 - 4 ¯ Rule: The rule involving both brackets and order of operations is called BODMAS. in a mathematical expression the operations are performed in the following order: first operation inside the bracket, then "of", division, multiplication, addition and subtraction. So, 28 - 22 - 7 + 24 ÷ 6 - 8 - 4 ¯ = 28 - 22 - 7 + 24 ÷ 6 - 4 = 28 - 22 - 7 + 24 ÷ 2 = 28 - 22 - 7 + 12 = 28 - 22 - 19 = 28 - 3 = 25

Using brackets formulate the numerical expression for the following word problems. Find 1 2 of the difference of 101 and the product of 13 and 7 .

To solve: 1 2 of the difference of 101 and product of 13 and 7 So, 1 2 101 - 13 × 7 Rule: The rule involving both brackets and order of operations is called BODMAS. in a mathematical expression the operations are performed in the following order: first operation inside the bracket, then "of", division, multiplication, addition and subtraction. So, 1 2 101 - 13 × 7 = 1 2 101 - 91 = 1 2 10 = 5