Six identical parallel metallic large plates are located in air at equal distances d to neighbouring plates. The area of each plate is A. Some of the plates are connected by conducting wires to each other. The capacitance of the system of plates between two points $P$ and $Q$ in $\mathrm{pF}$ is : (Take $\mathrm{A}=0.05{ \mathrm{m}}^2, \mathrm{d}=17.7 \mathrm{mm},{\epsilon }_0=8.85\times {10}^{-12} \mathrm{F} {\mathrm{m}}^{-1}$).

In the given circuit diagram,

$E=5 \mathrm{V}, r=1 \mathrm{\Omega }, R_2=4 \mathrm{\Omega }, R_1=R_3=1 \mathrm{\Omega }$ and $C=3 \mu \mathrm{F}$

Then, what will be the numerical value of charge on each plates of the capacitor.

Calculate the amount of charge on capacitor of $4 \mathrm{\mu F}.$ The internal resistance of battery is $1\mathrm{\Omega }:$

The equivalent capacitance between $A$ and $B$ is,

In the circuit shown, find $C$ if the effective capacitance of the whole circuit is to be $0.5 \mu F.$ All values in the circuit are in $\mu F.$

Find the equivalent capacitance between two points $A$ & $B$, for given figure (electric circuit) [Capacitance of each capacitor is $\mathrm{C}=3 \mu \mathrm{F}$]

Five identical capacitors, of capacitance $20 \mathrm{\mu F}$ each, are connected to a battery of $150 \mathrm{V},$ in a combination as shown in the diagram. What is the total amount of charge stored?

The figure shows a capacitor of capacitance $\mathrm{C}$ connected to a battery via a switch, having a total charge ${\mathrm{Q}}_0$ on it, in steady-state. When the switch $\mathrm{S}$ is turned from position $\mathrm{A}$ to position $\mathrm{B}$, the energy dissipated in the circuit is

Three capacitances, each of 3 $\mu \text{F}$, are provided. These cannot be combined to provide the resultant capacitance of :

In the circuit shown in the figure, the total charge is $750 \mu C$ and the voltage across capacitor $C_2$ is $20 \mathrm{V}$. Then the charge on capacitor ${\mathrm{C}}_2$ is :

For the arrangement of capacitors as shown in the circuit, the effective capacitance between point $A$ and $B$ is (capacitance of each capacitor is $4\mu F)$

In the circuit shown, charge on the $5\mu \mathrm{F}$  capacitor is :