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Sodium metal crystallises in BCC lattice with cell edge, $a = 4.29 Å .$ What is the radius of the sodium atom?

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Important Questions on Solid State

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IMPORTANT

Comprehensive Guide to VITEEE Chemistry. Other applicable Exams - JEE Main, BITSAT, SRM JEE, MHT-CET, K-CET, EAMCET, AMU & Other State Engg. Entrance Exams>Chapter 6 - Solid State>Exercise 2>Q 11

A metallic element crystallises into a lattice containing a sequence of layers of

ABABAB . . . . .

. Any packing of spheres leaves out voids in the lattice. What percentage by volume of this space is empty space?

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Comprehensive Guide to VITEEE Chemistry. Other applicable Exams - JEE Main, BITSAT, SRM JEE, MHT-CET, K-CET, EAMCET, AMU & Other State Engg. Entrance Exams>Chapter 6 - Solid State>Exercise 2>Q 12

Which of the following statements is wrong?

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Comprehensive Guide to VITEEE Chemistry. Other applicable Exams - JEE Main, BITSAT, SRM JEE, MHT-CET, K-CET, EAMCET, AMU & Other State Engg. Entrance Exams>Chapter 6 - Solid State>Exercise 2>Q 13

In a solid

' AB'

, having the

NaCl

structure,

' A'

atoms occupy the corners of the cubic unit cell. If all the face-centred atoms along one of the axes are removed, the resultant stoichiometry of the solid is

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Comprehensive Guide to VITEEE Chemistry. Other applicable Exams - JEE Main, BITSAT, SRM JEE, MHT-CET, K-CET, EAMCET, AMU & Other State Engg. Entrance Exams>Chapter 6 - Solid State>Exercise 2>Q 14

Argon crystallizes in a structure in which the atoms are located at the positions

(0, 0, 0), (0, \frac{1}{2}, \frac{1}{2}), (\frac{1}{2}, 0, \frac{1}{2})

and

(\frac{1}{2}, \frac{1}{2}, 0)

. The unit cell is

HARD

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Comprehensive Guide to VITEEE Chemistry. Other applicable Exams - JEE Main, BITSAT, SRM JEE, MHT-CET, K-CET, EAMCET, AMU & Other State Engg. Entrance Exams>Chapter 6 - Solid State>Exercise 2>Q 15

Consider the radii

0.095 nm ({Na}^{+}), 0.181 nm ({Cl}^{-}),

0.074 nm ({Zn}^{2 +}), 0.184 nm (S^{2 -}), 0.068 nm ({Ti}^{4 +}),

0.140 nm (O^{2 -}) and 0.169 nm ({Cs}^{+}) .

Choose the correct option from the following. (Use radius ratio rules)

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Comprehensive Guide to VITEEE Chemistry. Other applicable Exams - JEE Main, BITSAT, SRM JEE, MHT-CET, K-CET, EAMCET, AMU & Other State Engg. Entrance Exams>Chapter 6 - Solid State>Exercise 2>Q 16

The non-stoichiometric compound, ${Fe}_{0.94} O$ is formed when $x %$ of ${Fe}^{2 +}$ ions are replaced, such that each ${Fe}^{2 +}$ ion is replaced by $2 / 3 {Fe}^{3 +}$ ions. $x$ is

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Comprehensive Guide to VITEEE Chemistry. Other applicable Exams - JEE Main, BITSAT, SRM JEE, MHT-CET, K-CET, EAMCET, AMU & Other State Engg. Entrance Exams>Chapter 6 - Solid State>Exercise 2>Q 17

NaCl

is doped with

2 \times 10^{- 3}

mole

%

{SrCl}_{2}

. The concentration of cation vacancies is

MEDIUM

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IMPORTANT

Comprehensive Guide to VITEEE Chemistry. Other applicable Exams - JEE Main, BITSAT, SRM JEE, MHT-CET, K-CET, EAMCET, AMU & Other State Engg. Entrance Exams>Chapter 6 - Solid State>Exercise 2>Q 18

{NH}_{4} Cl

crystallises in a BCC lattice with the edge length of the unit cell equal to

387 pm

. If the radius of the

{Cl}^{-}

ion is

181 pm

, the radius of the

{NH}_{4}^{+}

ions is:

Sodium metal crystallises in BCC lattice with cell edge, a=4.29 Å. What is the radius of the sodium atom?

Important Questions on Solid State

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Sodium metal crystallises in BCC lattice with cell edge, $a = 4.29 Å .$ What is the radius of the sodium atom?