Solve $|x+3|=8$ using modulus function definition.

The area bounded by the curves $y=\left|x-1\right|+\left|x-2\right|$ and $y=3$ is equal to

The minimum value of $f\left(x\right) = |3 - x| + |2 + x| + |5 - x|$ is:

Let $f\left(x\right)=x^2-5x+6, g\left(x\right)=f\left(\right|x\left|\right), h\left(x\right)=\left|g\right(x\left)\right| \mathrm{and} \varphi \left(x\right)=h\left(x\right)-\left(x\right)$ are four functions, where $\left(x\right)$ is the integral function of $x\ge x$. Then, the number of solutions of the equation, $g\left(x\right)=0$ is