Solve the following by transposition method. x 2 = - x - 2

Given equation, x 2 = - x - 2 . We solve the given equation by the transposition method. Transposing 2 from LHS to RHS and reversing operation, x = 2 × - x - 2 x = - 2 x - 4 Transposing 2 x from RHS to LHS and reversing operation, x + 2 x = - 4 3 x = - 4 Transposing 3 from LHS to RHS and reversing operation, x = - 4 3 Hence, the value of x is - 4 3 .

Solve the following by transposition method. x 2 = - x - 2

Given equation, x 2 = - x - 2 . We solve the given equation by the transposition method. Transposing 2 from LHS to RHS and reversing operation, x = 2 × - x - 2 x = - 2 x - 4 Transposing 2 x from RHS to LHS and reversing operation, x + 2 x = - 4 3 x = - 4 Transposing 3 from LHS to RHS and reversing operation, x = - 4 3 Hence, the value of x is - 4 3 .

Frame 3 equations for the solution t = 1 2 .

Given equation: t = 1 2 . To find: Frame 3 equations for the given equation. Multiply 10 on both sides to the given equation. 10 × t = 10 × 1 2 10 t = 5 . . . ( 1 ) Add 10 on both sides to the given equation. 10 + t = 10 + 1 2 RHS: 10 + 1 2 = 20 + 1 2 = 21 2 10 + t = 21 2 . . . ( 2 ) Subtract 10 on both sides to the given equation, t - 10 = 1 2 - 10 RHS: 1 2 - 10 = 1 - 20 2 = - 19 2 t - 10 = - 19 2 . . . ( 3 ) Hence, equation ( 1 ) , equation ( 2 ) , equation ( 3 ) are the required three equations.