Solve the following equation and check the result: 3 x 2 = 9

Given, 3 x 2 = 9 3 x 2 = 9 Transposing constant terms from L.H.S to R.H.S. 3 x = 9 × 2 3 x = 18 x = 18 3 x = 6 Hence, x = 6 is the solution of the equation 3 x 2 = 9 Check: Put x = 6 in the equation: 3 × 6 2 = 9 9 - 9 Here, we get L.H.S = R.H.S Therefore, the value of x is 6 .

Solve the following equation and check the result: 3 x 2 = 9

Given, 3 x 2 = 9 3 x 2 = 9 Transposing constant terms from L.H.S to R.H.S. 3 x = 9 × 2 3 x = 18 x = 18 3 x = 6 Hence, x = 6 is the solution of the equation 3 x 2 = 9 Check: Put x = 6 in the equation: 3 × 6 2 = 9 9 - 9 Here, we get L.H.S = R.H.S Therefore, the value of x is 6 .

Solve the following equation and check the result: 1 2 x + 9 = 14

Given, 1 2 x + 9 = 14 Transposing constant terms from L.H.S to R.H.S. x 2 = 14 - 9 x 2 = 5 x = 5 × 2 x = 10 Hence, x = 10 is the solution of the equation 1 2 x + 9 = 14 Check: Put x = 10 in the equation: 1 2 × 10 + 9 = 14 5 + 9 = 14 14 = 14 Here, we get L.H.S = R.H.S Therefore, the value of x is 10 .

Solve the following equation and check the result: x 2 + x 3 = 1

Given, x 2 + x 3 = 1 Here, denominators are not same, so find the L.C.M of denominators to equal. L.C.M of 2 , 3 = 6 3 x + 2 x 6 = 1 Transposing constant terms from L.H.S to R.H.S. 5 x = 1 × 6 5 x = 6 x = 6 5 Hence, x = 6 5 is the solution of the equation x 2 + x 3 = 1 Check: Put x = 6 5 in the equation: 6 5 2 + 6 5 3 = 1 6 5 × 1 2 + 6 5 × 1 3 = 1 3 5 + 2 5 = 1 5 5 = 1 1 = 1 Here, we get L.H.S = R.H.S Therefore, the value of x is 6 5 .

Solve the following equation and check the result: 1 2 - 3 x = 0

Given, 1 2 - 3 x = 0 Transposing constant terms from L.H.S to R.H.S. - 3 x = - 1 2 x = 1 2 × 3 x = 1 6 Hence, x = 1 6 is the solution of the equation 1 2 - 3 x = 0 Check: Put x = 1 6 in the equation: 1 2 - 3 × 1 6 = 0 1 2 - 1 2 = 0 0 = 0 Here, we get L.H.S = R.H.S Therefore, the value of x is 1 6 .

Solve the following equation and check the result: x - 3 5 - 1 = 2

Given, x - 3 5 - 1 = 2 Transposing constant terms from L.H.S to R.H.S. x - 3 5 = 2 + 1 x - 3 5 = 3 x - 3 = 15 x = 15 + 3 x = 18 Hence, x = 18 is the solution of the equation x - 3 5 - 1 = 2 Check: Put x = 18 in the equation: 18 - 3 5 - 1 = 2 15 5 - 1 = 2 3 - 1 = 2 2 = 2 Here, we get L.H.S = R.H.S Therefore, the value of x is 18 .