
Sound waves of v=600Hz fall normally on a perfectly reflecting wall. The shortest distance from the wall at which all particles will have maximum amplitude of vibration will be (speed of sound=)

Important Questions on Waves


(velocity of sound




Two identical coherent sound sources and with frequency are apart. An observer standing equidistant from the source and at a perpendicular distance of from the line hears maximum sound intensity.
When he moves parallel to , the sound intensity varies and is a minimum when he comes directly in front of one of the two sources. Then, a possible value of is close to (the speed of sound is )

The equations of two waves are given by :
These waves are simultaneously passing through a string. The amplitude of the resulting wave is :












Incident wave is reflected by an obstacle at which reduces intensity of reflected wave by Due to superposition, the resulting wave consists of a standing wave and a travelling wave given by where and c are positive constants.
Amplitude of reflected wave is

