Study the following information and answer the question:

A€B means "A is neither smaller than nor equal to B"
A&B means "A is not smaller than B"
A¥B means "A is neither smaller than nor greater than B"
A₩B means "A is neither greater than nor equal to B"
A$B means "A is not greater than B

Statement:

$I\yen J\&K; K€L\$Q₩R\yen S$

Conclusion:

$$\begin{gathered} I. I\&R \\ II. I₩R \\ III. L€I \end{gathered}$$

In the following question choose the correct alternative assuming $\alpha$ stands for $=$; $\beta$ stands for $>$; $\gamma$ stands for $<$ and $\delta$ stands for $\ne$.

If $a^{2}x\alpha byz, czx\alpha b^{2}y$ and $c^{2}z\alpha axy$, then

In a coded language, the mathematical operators have been placed in clock. The position of operator is the position of minute hand. The coding is as follows $\text{'}+\text{'}$ at $7:25$, $\text{'}\times \text{'}$ at $5:15$, $\text{'}÷\text{'}$ at $9:00$, $\text{'}<\text{'}$ at $10:55$, $\text{'}>\text{'}$ at $3:30$, $\text{'}=\text{'}$ at $1:05$, $\text{'}-\text{'}$ at $11:25$. If positions of $\text{'}+\text{'}, \text{'}–\text{'}, \text{'}\times \text{'}, \text{'}÷\text{'}, \text{'}<\text{'}, \text{'}>\text{'}, \text{'}=\text{'}$ changed by rotation of angle $30°, 60°, 90°, 120°, 150°, 180°, 210°$ in the clockwise and anti-clockwise alternatively, then which of the following is correct statement?

In the following question choose the correct alternative assuming $\alpha$ stands for $=$; $\beta$ stands for $>$; $\gamma$ stands for $<$ and $\delta$ stands for $\ne$.

If $ax\gamma by, bx\alpha cz$ and $b^2\alpha ac$ then

In the given below question substitutes for various mathematical symbols, followed by a question involving the calculation of an expression is given. Put the real signs in the given equations and solve the question.

If $+$ means $÷$, $÷$ means $-$, $-$ means $\times$, $\times$ means $+$, then

$64\times 8÷6-4\times 2=?$  

In the following question choose the correct alternative assuming $\alpha$ stands for $=$; $\beta$ stands for $>$; $\gamma$ stands for $<$ and $\delta$ stands for $\ne$.

If $6x\alpha 5y$ and $2y\beta 3z$, then 

When $- \& =, 60 \& 20$ are interchanged, find which one of the following equations will be correct?

Follow the instruction and choose the correct option.

If $\mathrm{\Delta }$ means $>$, $\square$ means $<$, $○$ means $=$ and $\#$ means $\ne$ and $\mathrm{A}○\mathrm{B} , \mathrm{C} \mathrm{\Delta } \mathrm{D}$ as well as $\mathrm{D}\square \mathrm{A}$, then which of the following is true?

In this question, $\text{'}∆\text{'}$ means "Greater than" $\square$ means "Less than",$\text{'}\varphi \text{'}$  means "equal to" $\oplus$ means "not equal to"
If $\mathrm{C}∆\mathrm{A}$, $\mathrm{A}\square \mathrm{B}$, $\mathrm{D\varphi B}$ and $\mathrm{B}\oplus \mathrm{C}$, then choose the correct option in the following

In the following question choose the correct alternative assuming $\alpha$ stands for $=$; $\beta$ stands for $>$; $\gamma$ stands for $<$ and $\delta$ stands for $\ne$.

If $abxy\alpha c^{2}z, bx\beta ay$ and $b^2\alpha ac$, then

To get the correct equation, choose which set of signs from the given alternatives to be substituted sequentially in place of $\left(*\right)$

$13 * 4 * 5 * 12 * 6$

If 

$\text{'}+\text{'}$ implies $\text{'}\mathrm{go}\text{'}$

$\text{'}-\text{'}$ implies $\text{'}\mathrm{to}\text{'}$

$\text{'}\times \text{'}$ implies $\text{'}\mathrm{walk}\text{'}$

$\text{'}=\text{'}$ implies $\text{'}\mathrm{early}\text{'}$

$\text{'}<\text{'}$ implies $\text{'}\mathrm{before}\text{'}$

$\text{'}>\text{'}$ implies $\text{'}\mathrm{Sun}\text{'}$

$\text{'}÷\text{'}$ implies $\text{'}\mathrm{rise}\text{'}$

then, identify the correct expression:

In the following question choose the correct alternative assuming $\alpha$ stands for $=$; $\beta$ stands for $>$; $\gamma$ stands for $<$ and $\delta$ stands for $\ne$.

A clock is so placed that at $12$ Noon its minute hand points towards West. The mathematical operators have been placed at the minute hand position at particular time given below:

$\text{'}<\text{'}$ at fifteen minutes before noon
$\text{'}=\text{'}$ at ten minutes past two
$\text{'}>\text{'}$ at half past six
$\text{'}\times \text{'}$ at twenty minutes past seven
$\text{'}+\text{'}$ at quarter past eight
$\text{'}-\text{'}$ at nine o’ clock
$\text{'}+\text{'}$ at five minutes to ten

Which is the correct mathematical expression based on above information?

To get the correct equation, choose which set of signs from the given alternatives to be substituted sequentially in place of $\left(*\right)$

$15 * 3 * 5 * 16 * 41$