EASY

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Sulphur and rest of the elements of group 16 are less electronegative than oxygen. Therefore, their atoms cannot take up electrons easily. They can acquire ns²np⁶ configuration by sharing two electrons with the atoms of other elements and thus, exhibit +2 oxidation state in their compounds. In addition to this, their atoms have vacant d-orbitals in their valence shell to which electrons can be promoted from the p and s-orbitals of the same shell. As a result, they can show +4 and +6 oxidation states.

Like sulphur, oxygen does not show +4 and +6 oxidation states. The reason is :

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Important Questions on Stoichiometry

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

The oxidation number of sulphur in

S_{8}

molecule is

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

The oxidation states of

Cr

[Cr {(H_{2} O)}_{6}] {Cl}_{3}, [Cr {(C_{6} H_{6})}_{2}]

and

K_{2} [Cr {(CN)}_{2} {(O)}_{2} (O_{2}) ({NH}_{3})]

, respectively, are:

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

In acidic medium,

H_{2} O_{2}

changes

C r_{2} O_{7}^{- 2}

C r O_{5}

which has two

(- O - O -)

bonds Oxidation state of

C r

C r O_{5}

is:

MEDIUM

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

In the reaction of gold with aquaregia, oxidation state of Nitrogen changes from

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

The oxidation number of sulphur is

+ 4

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

Oxidation number of potassium in

K_{2} O, K_{2} O_{2}

and

K O_{2},

respectively, is:

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

The correct structure of tribromooctaoxide is:

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

What is the change in oxidation number of carbon in the following reaction?

{CH}_{4} (g) + 4 {Cl}_{2} (g) \to {CCl}_{4} + 4 HCl (g)

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

The pair of compounds having metals in their highest oxidation state is

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

Two elements, X and Y have atomic numbers 33 and 17, respectively. The molecular formula of a stable compound formed between them is-

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

{CH}_{4} (g) + 4 {Cl}_{2} (g) \to {CCl}_{4} (1) + 4 HCl (g)

In the above reaction, the change of oxidation state of carbon is

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

Identify the compound in which phosphorus exists in the oxidation state of +1.

HARD

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

The oxidation states of transition metal atoms in

K_{2} {Cr}_{2} O_{7}, {KMnO}_{4}

and

K_{2} {FeO}_{4},

respectively, are

x, y

and

z

. The sum of

x, y

and

z

is______

MEDIUM

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

The oxidation state of sulphur in

H_{2} S_{2} O_{7}

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

Identify the incorrect statement.

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

The oxidation number of nitrogen atoms in

{NH}_{4}, {NO}_{3}

are

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

The oxidation number of the underlined atom in the following species is given. Identify the incorrect statement.

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

The metal with the highest oxidation state present in

K_{2} {CrO}_{4}, {NbCl}_{5} and {MnO}_{2}

is-

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

The oxidation states of P atom in

P O C l_{3}, H_{2} P O_{3}

and

H_{4} P_{2} O_{6}

, respectively, are

EASY

Chemistry>Physical Chemistry>Stoichiometry>Oxidation Number

An element

X

shows

+ 3

, oxidation state in its compounds. Out of the four compounds given below, choose the incorrect formula for the element

X

Important Questions on Stoichiometry

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